Answer:
The concentration of sulfuric acid is 0.0033 M
Explanation:
Step 1: Data given
Volume of the sulfuric acid (H2SO4) = 24.0 mL = 0.024 L
Volume of NaOH = 1.8 mL = 0.0018 L
Molarity of NaOH = 0.0882 M
Step 2: The balanced equation
H2SO4 + 2NaOH → Na2SO4 + 2H2O
Step 3: Calculate the concentration of H2SO4
b*Ca*Va = a * Cb * Vb
⇒b = the coefficient of NaOH = 2
⇒Ca = the concentration of H2SO4 = TO BE DETERMINED
⇒Va = the volume of H2SO4 = 0.024 L
⇒a = the coefficient of H2SO4 = 1
⇒Cb = the concentration of NaOH = 0.0882 M
⇒Vb = the volume of NaOH = 0.0018 L
2* Ca * 0.024 = 1 * 0.0882 * 0.0018
0.048 * Ca = 0.00015876
Ca = 0.0033 M
The concentration of sulfuric acid is 0.0033 M
