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Lorico [155]
3 years ago
12

If 3.0 g of NH3 reacts with 5.0 g of HCl, what is the limiting reactant?

Chemistry
1 answer:
ELEN [110]3 years ago
7 0
<h2>Answer:HCl</h2>

Explanation:

\text{number of moles}=\frac{\text{given mass}}{\text{molar mass}}

For NH_{3},

\text{given mass}=3g

\text{molar mass}=14+3=17g

n_{NH_{3}}=\frac{3}{17}=0.176

For HCl,

\text{given mass}=5g

\text{molar mass}=1+35.5=36.5g

n_{HCl}=\frac{5}{36.5}=0.136

The reaction between NH_{3} and HCl is

NH_{3}+HCl→NH_{4}Cl

So,one mole of NH_{3} requires one mole of HCl

0.176 moles of NH_{3} requires 0.176 moles of HCl

But there are only 0.136 moles of HCl available.

HCl will be consumed first.

So,HCl is the limiting reagent.

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Step 1: Data given

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