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Delicious77 [7]
2 years ago
10

HELPPPPP NEED FOR ESSAY Vicente is going to spend the afternoon in his yard. He has the choice to get in the pool, lay on a cott

on chaise longue, sit on the porcelain tile bordering the pool, or sit on a plastic chair. The specific heats of these items are: Water = 4.19 J/g•°C Cotton = 1.30 J/g•°C Porcelain = 1.07 J/g•°C Plastic = 1.67 J/g•°C Based on the specific heat values given, where is the coolest location for Vicente to be?
Chemistry
2 answers:
Rashid [163]2 years ago
8 0
<h2>Answer : Option A) Water = 4.19 J/g.°C</h2><h3>Explanation :</h3>

According to the given option the coolest location for Vicente will be the pool. As higher is the value of the specific heat of the item/material lower will be the heating rate of that item/material.

So, when comparing the given options, water seems to be higher in specific heat compared to others. This clearly indicates that it will be the coolest location for Vicente to spend his afternoon.


velikii [3]2 years ago
6 0
The higher the specific heat, the longer it will take to get hot. The coolest location for Vicente to be would be the water, because its specific heat is higher than the other locations. 

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Mr Singh is cooking using wo pans of oiling water. Both pans are made of steel, but one pan has a much thicker base than the oth
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Complete the electron-dot structure of s-allylcysteine, showing all lone-pair electrons.
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7 0
3 years ago
A gaseous compound is 30.4 % N and 69.6% OF. A 5.25 g sample of the gas occupies a volume of 1.00 L and exerts a pressure of 958
Harman [31]

Answer:

The molecular formula = N2O4

Explanation:

<u>Step 1</u>: Data given

A gaseous compound is 30.4 % N and 69.6%

Mass of the compound = 5.25 grams

Volume of the gas = 1.00 L

Pressure of the gas = 958 mmHg = 1.26 atm

Temperature of the gas = -4 °C = 273 -4°C = 269 Kelvin

Molar mass of N = 14 g/mol

Molar mass of O = 16 g/mol

<u>Step 2</u>: Calculate mass of N

Mass of Nitrogen = 5.25 grams * 0.304 = 1.596 grams

<u>Step 3:</u> Calculate mass of O

Mass of Oxygen = 5.25 grams * 0.696 = 3.654 grams

<u>Step 4:</u> Calculate number of moles N

Number of moles N = Mass of N/ Molar mass of N

Moles of N = 1.596 grams / 14g/mol

Moles of N = 0.114 moles N

<u>Step 5:</u> Calculate moles of O

Moles O = 3.654 grams / 16 g/mol

Moles 0 = 0.2884 moles

<u>Step 6:</u> Calculate empirical formule

We calculate the empirical formule by dividing number of moles by the smallest number of mol

N : 0.114 / 0.114 = 1

O: 0.2284 / 0.114 = 2

Empirical formule = NO2

<u>Step 7: </u>Calculate number of moles of 5.25 g sample via gas law:

p*V = nRT

⇒ with p = the pressure = 1.26 atm

⇒ with v = 1.00 L

⇒ with n = the number of moles = TO BE DETERMINED

⇒ with R = the gas constant = 0.08206 L*atm/ K*mol

⇒ with T = the temperature = 269 K

number of moles n = (p*V)/(R*T)

n = (1.26*1L)/(0.08206*269)

n = 0.057 mol  

<u>Step 8:</u> Calculate molar mass of the compound

This means 5.25 grams of the gas = 0.057 moles

So 1 mol of the compound has a molar mass of: 5.25 / 0.057 = 92.11 g/mol

<u>Step 9</u>: Calculate molar mass of the empirical formula NO2

N = 14 g/mol

O = 16 g/mol

NO2 = 14 + 16 + 16 = 46 g/mol

The empirical formule NO2 has a molar mass of 46 g/mol

<u>Step 10</u>: Calculate molecular formula

92.11 / 46 = 2

This means the empirical formula should be multiplied by 2

2*(NO2) = N2O4

The molecular formula = N2O4

8 0
2 years ago
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