Y<-18 or y>18 would work i think
Answer:
EF = BC = a ÐF is a right angle. FD = CA = b triangle EF = BC = a angle F is a right angle. FD = CA = b In triangle DEF, By Pythagoras Theorem, a2 + b2 = c2 the given AB=c= a^2 + b^2 square root Theorefore AB = DE But by construction, BC = EF and CA = FD triangle ABC congruent to DEF (S.S.S
We have given that Δ ABC is similar to Δ CBD and Δ ABC is similar to Δ ACD according to the attached picture.
Because of the similarity the corresponding sides are proportional. Then a/c = f/a
and b/e = c/b. If we cross multiply, we'll get
a² = cf and b² = ce
If we add these equalities together, we'll get
a² + b² = c (f + e)
From the beginning, we know that c = e+f
Then, the final result is:
a² + b² = c²
Membership is discounted $2 for first month
c=cost of one month
d=discount=$2
x=# of months
xc - 2= total cost
x for 1 month is 1, c is always 12, -2 is constant
1 x(12) - 2=10 for first month
8 months
8c -2=total cost for 8 months
8 x 12 - 2= 94 for 8 months
Im pretty sure its 1.0296 multiplied by 10 to the tenth power
a) Due to you have a right triangle, in order to calculate the value of d, use the Pythagorean thorem:
Hence, the distance d is approximately 63.2m
b) To find the angle of elevation, use the sine function of θ, as follow:
Hence, the angle of elevation is approximately 19.8°