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Liono4ka [1.6K]
2 years ago
13

Of 500 new electronic products, 280 were intended for people over the age of 16, and 320 used a rechargeable battery. Of those p

roducts with a rechargeable battery, 150 were intended for those under the age of 16. What is the probability that a new electronic product is intended for someone over the age of 16 or uses a rechargeable battery?
choices:
430/500 = 0.86
450/500 = 0.9
110/500 = 0.22
280/500 = 0.56
Mathematics
2 answers:
Mkey [24]2 years ago
7 0

Answer:

D. 280/500 = 0.56

Step-by-step explanation:

280 are intended for people over 16 and 320 use a rechargeable battery.

320-150 = 170 (intended for those under the age of 16)

The answer would be D because you need to take the highest number of products (280) that would satisfy the requirements.

skad [1K]2 years ago
4 0

Answer:

450/500 = 0.9sorry if it's wrong

Step-by-step explanation:

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Answer:

A = 29

Step-by-step explanation:

a triangle is equal to 180 so the bottom triangle you add 34 + 26 = 60 --> 180-60 = 120  ---> the triangle on top is 120 + 31 = 151 -----> 180-151 = 29

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Which list shows the following numbers in order from least to greatest
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Answer:

1. 3 9/20

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3 years ago
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A 500 gallon bathtub is being filled with water. Eighty gallons of water are in the bathtub after 4 minutes. How long will it ta
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8 0
3 years ago
Find the monthly interest payment in the situation described below. Assume that the monthly interest rate is 1 divided by 12 of
asambeis [7]

The monthly interest payment is 162

<h3>What is Interest?</h3>

Interest, in its most simple form, is calculated as a percent of the principal.

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=0.02×$675

= $13.50.

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brainly.com/question/1435782

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3 0
1 year ago
1. The national mean (μ) IQ score from an IQ test is 100 with a standard deviation (s) of 15. The dean of a college wants to kno
Nat2105 [25]

Answer:

We conclude that the mean IQ of her students is different from the national average.

Step-by-step explanation:

We are given that the national mean (μ) IQ score from an IQ test is 100 with a standard deviation (s) of 15.

The dean of a college want to test whether the mean IQ of her students is different from the national average. For this, she administers IQ tests to her 144 students and calculates a mean score of 113

Let, Null Hypothesis, H_0 : \mu = 100 {means that the mean IQ of her students is same as of national average}

Alternate Hypothesis, H_1 : \mu\neq 100  {means that the mean IQ of her students is different from the national average}

(a) The test statistics that will be used here is One sample z-test statistics;

               T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ N(0,1)

where, Xbar = sample mean score = 113

              s = population standard deviation = 15

             n = sample of students = 144

So, test statistics = \frac{113-100}{\frac{15}{\sqrt{144} } }

                             = 10.4

Now, at 0.05 significance level, the z table gives critical value of 1.96. Since our test statistics is more than the critical value of z which means our test statistics will fall in the rejection region and we have sufficient evidence to reject our null hypothesis.

Therefore, we conclude that the mean IQ of her students is different from the national average.

3 0
3 years ago
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