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madreJ [45]
3 years ago
5

It would be impossible to build a microscope that could use visible light to see the molecular structure of a crystal because. I

t would be impossible to build a microscope that could use visible light to see the molecular structure of a crystal because. lenses cannot be ground with fine enough precision. diffraction limits the resolving power to about the size of the wavelength of the light used. lenses with enough magnification cannot be made. lenses cannot be placed in the correct place with enough precision. More than one of the above is correct.
Physics
1 answer:
Serhud [2]3 years ago
6 0

Answer:

the correct one is: a diffraction limits the resolving power to approximately the size of the wavelength of the light used

Explanation:

To be able to solve two structures with a light source, the Rayleigh criterion must be met that stable the two structures are solved when the first minimum of diffraction at one point is in the code of the first maximum of the other point

Using this criterion we can find an expression for the first minimization of the diffraction spectrum m = 1

     sin θ tea = λ / a

now the structure of the comatose has a separation of around 1 nm and the wavelength of visible light ranges from 400 to 700 nm, when substituting we find

           sin θ = 400/1 10

           sin θ  = 400

           sin θ  = 700/1

           sin θ  = 700

These values ​​are neither impossible since the sin function is bounded between -1 to 1, so we cannot see the diffraction

When reviewing the different statements, the correct one is: a diffraction limits the resolving power to approximately the size of the wavelength of the light used:

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Prove that young modulus of elasticity and pressure have the same dimensions​
ivann1987 [24]

Answer:

The dimensions of Young's Modulus, as well as material stress, are the same as pressure because stress is like pressure in a solid, except with some key differences that warrant the use of different terminology.

8 0
3 years ago
One of the reasons you love your home is because every side of your home faces South. One day, while talking on the phone, you h
ExtremeBDS [4]

The bear is white in color because it is a polar bear.

<h3>What are the color of bears?</h3>

Bears are very large carnivorous animals found around the cold regions of the Arctic or North Pole.

The color of bears, may be brown, black or white depending on how far North the bears are found.

Bears found close to the Arctic or North pole are white polar bears.

Based on the description of the house, every side of the home faces South meaning that the individual lives in the North pole.

Therefore, the color of the bear will be white.

in conclusion, polar bears are white in color.

Learn more about polar bears at: brainly.com/question/21618662

#SPJ1

8 0
2 years ago
The transfer of energy carried in rays is called convection true or false
Oxana [17]
False that is radiation
4 0
3 years ago
LSE
Zinaida [17]
B) initial speed (u)=3
final speed (v)=8
time (t)= 10
acceleration (a)=?

v=u+at
8=3+a(10)
5=10a
a=1/2= 0.5 m/s²

c)displacement (s)=?
1st section of journey

v ²=u ²+2as
8 ²=3 ²+2(0.5)s
64=9+1s
s=55meters

2nd section of journey
a=0
t=7
u=8
s=?

s=ut+1/2at²
s=8(7)+1/2(0)(7 ²)
s=56 meters

56+55= 111 meters

(For graph x axis =time (sec) & y axis= velocity (m/s))

6 0
3 years ago
The rotational inertia of a thin rod about one end is 1/3 ML2. What is the rotational inertia of the same rod about a point loca
zlopas [31]

Answer:

The value is  I = 0.0932 ML ^2  

Explanation:

From the question we are told that

  The rotational inertia about one end is I_R =  \frac{1}{3} ML^2

   The location of the axis of rotation considered is d =  0.4 L

Generally the mass of the portion of the rod from the axis of rotation considered to the end of the rod is  0.4 M

Generally the length of the rod from the its beginning to the axis of rotation consider is

      k = 1 - 0.4 L = 0.6L

Generally the mass of the portion  of the rod from the its beginning to the axis of rotation consider is

    m  =  1- 0.4 M = 0.6 M

Generally the rotational inertia about the axis of rotation consider for the first portion of the rod is

     I_{R1} =  \frac{1}{3} (0.6 M )(0.6L)^2

    I_{R1} =  \frac{1}{3} (0.6 M )L^2 0.6^2

Generally the rotational inertia about the axis of rotation consider for the second  portion of the rod is

     I_{R2} =  \frac{1}{3} (0.6 M )(0.6L)^2

=> I_{R2} =  \frac{1}{3} (0.4 M )(0.4L)^2

=>  I_{R2} =  \frac{1}{3} (0.4 M )L^2 0.4^2

Generally by the principle of superposition that rotational inertia of the rod at the considered axis of rotation is

  I =   \frac{1}{3} (0.6 M )L^2 0.6^2 +   \frac{1}{3} (0.4 M )L^2 0.4^2

=>   I =  \frac{1}{3} ML ^2  [0.6 * (0.6)^2 + 0.4 * (0.4)^2 ]

=>   I = 0.0932 ML ^2  

8 0
3 years ago
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