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3 years ago

Describe how newtons third law is related to fluid pressure.

1 answer:

3 0

Fish swimming forward in the water, the water gets pushed backward because the fish moving forward is forcing the water to move backward, the motion forward and backward are the same, they are opposite and equal.

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A man is walking away from a lamppost with a light source h = 6 m above the ground. the man is m = 2 m tall. how long is the man

Llana [10]

Answer;

= 4 m is the length of the man's shadow.

Explanation;

2/x=6/(8+x) cross multiply.

6x=2(8+x)

6x=16+2x

6x-2x=16

4x=16

x=2=16/4

x=4 m. is the length of the man's shadow.

3 0

3 years ago

If an piano and an apple are dropped in a tunnel without air.which would hit the ground first

liq [111]

Answer:

the piano.

Explanation:

4 0

3 years ago

A 129-kg horizontal platform is a uniform disk of radius 1.61 m and can rotate about the vertical axis through its center. A 65.

LUCKY_DIMON [66]

Answer:

Moment of inertia of the system is 289.088 kg.m^2

Explanation:

Given:

Mass of the platform which is a uniform disk = 129 kg

Radius of the disk rotating about vertical axis = 1.61 m

Mass of the person standing on platform = 65.7 kg

Distance from the center of platform = 1.07 m

Mass of the dog on the platform = 27.3 kg

Distance from center of platform = 1.31 m

We have to calculate the moment of inertia.

Formula:

MOI of disk = $\frac{MR^2}{2}$

Moment of inertia of the person and the dog will be mr^2.

Where m and r are different for both the bodies.

So,

Moment of inertia $(I_y_y )$ of the system with respect to the axis yy.

⇒ $I_y_y=I_d_i_s_k + I_m_a_n+I_d_o_g$

⇒ $I_y_y=\frac{M_d_i_s_k(R_d_i_s_k)^2}{2} +M_m(r_c)^2+M_d_o_g(R_c)^2$

⇒ $I_y_y=\frac{129(1.61)^2}{2} +65.7(1.07)^2+27.2(1.31)^2$

⇒ $I_y_y=289.088\ kg.m^2$

The moment of inertia of the system is 289.088 kg.m^2

7 0

3 years ago

Calculate the kinetic energy in joules of a 1500 kg automobile moving at 19 m/s

Svetlanka [38]

Using
KE = ½mv² = ½×1500×19×19 = 270750 joules

5 0

3 years ago

What is the speed of a commercial jet which travels form New York to Los Angeles (4800) in 6 hours

Colt1911 [192]

Answer:

$Speed = 800km}/hr$

Explanation:

Given

$Distance = 4800km$

$Time = 6hr$

Required

Determine the speed of the jet

The speed is calculated as:

$Speed = \frac{Distance}{Time}$

Substitute 4800 km for Distance and 6hr for Time

$Speed = \frac{4800km}{6hr}$

$Speed = 800km}/hr$

<em>Hence, the speed of the commercial jet is 800km/hr</em>

8 0

2 years ago