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2 years ago

What is the average velocity of atoms in 2.00 mol of neon (a monatomic gas)

Physics

2 answers:

Dimas [21]2 years ago

8 0

Answer:

v = 876 m/s

Explanation:

It is given that,

Number of mol of Neon is 2 mol

Temperature, T = 308 K

Mass, m = 0.02 kg

Value of R - 8.31 J/mol-K

We need to find the average velocity of atoms in 2.00 mol of neon. Neon is a monoatomic gas. Let v is the velocity. So,

$\dfrac{1}{2}mv^2=\dfrac{3}{2}nRT\\\\v=\sqrt{\dfrac{3nRT}{m}} \\\\v=\sqrt{\dfrac{3\times 2\times 8.314\times 308}{0.02}} \\\\v=876.47\ m/s$

So, the correct option is (B).

Alenkasestr [34]2 years ago

5 0

I think it is 887m/s I hope this helps if not I’m really sry

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3 years ago

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pishuonlain [190]

Answer:

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2 years ago