Answer:
Energy of Photon = 4.091 MeV
Explanation:
From the conservation of energy principle, we know that total energy of the system must remain conserved. So, the energy or particles before collision must be equal to the energy of photons after collision.
K.E OF electron + Rest Energy of electron + K.E of positron + Rest Energy of positron = 2(Energy of Photon)
where,
K.E OF electron = 3.58 MeV
Rest Energy of electron = 0.511 MeV
Rest Energy of positron = 0.511 MeV
K.E OF positron = 3.58 MeV
Energy of Photon = ?
Therefore,
3.58 MeV + 0.511 MeV + 3.58 MeV + 0.511 MeV = 2(Energy of Photon)
Energy of Photon = 8.182 MeV/2
<u>Energy of Photon = 4.091 MeV</u>
<span>The normal force is the support force exerted upon an object which is in contact with another stable object. For example, if a book is resting upon a surface, then the surface is exerting an upward force upon the book in order to support the weight of the book. The normal force in itseñf comes from the third law of Newton as a reactive force</span>
Answer:
Explanation:
For this case we can use the second law of Newton given by:
The friction force on this case is defined as :
Where N represent the normal force, 
the kinetic friction coeffient and a the acceleration.
For this case we can assume that the only force is the friction force and we have:
Replacing the friction force we got:
We can cancel the mass and we have:
And now we can use the following kinematic formula in order to find the distance travelled:
Assuming the final velocity is 0 we can find the distance like this:
An important aspect of fission reactions is that they produce free neutrons, which causes chain reactions.
