Question

Sea ice is frozen ocean water, which freezes at a temperture of about -1.8 degress celsius. What is the temperture in fahrenheit use the formula F=(c) (9/5)+32

Answer 1

Answer:

28.76 °F

Step-by-step explanation:

The temperture of sea ice frozen ocean water is about -1.8 °C .

We are to convert to a temperture in fahrenheit using the formula F=(c) (9/5)+32

°C = -1.8°C

°F=(c) (9/5)+32

= [(-1.8°C × 9/5) + 32]°F

= [-16.2/5 + 32]°F

= [-3.24 + 32]°F

= 28.76°F