The rate of increase of NH3 is 0.22M/s.
<h3>What is the balanced equation of the reaction?</h3>
The balanced equation of the reaction is given below:
- N2(g) + 3 H2(g) → 2 NH3(g)
The rate of decrease of N2 is half the rate of increase of NH3.
Rate of decrease of N2 = -0.11 M/s
Rate of increase of NH3 = 2 × +0.11 M/s = 0.22M/s.
In conclusion, the rate of formation of products is dependent on the rate of disappearance of reactants.
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Answer: 8.28g Na
Explanation: use ideal gas law
PV= nRT
Solve for moles of Cl2
n= PV/ RT
Substitute:
= 1 atm x 4.0 L / 0.08205 L.atm/ mol. K x 273 K
= 0.18 moles Cl2
Do stoichiometry to solve for m of Na
2 Na + Cl2 => 2 NaCl2
=0.18 moles Cl2 x 2 mol Na/ 1 mol Cl2 x 23g Na / 1 mol Na
= 8.28 g Na.
Answer:
4- radioactive isotopes
Explanation:
I don't remember exactly but this question was on the regents
Just need some point sorry
The answer is B. A good way determine this is how far right the element is on the periodic table. The further right the element is, the more electronegative it is meaning it is more willing to accept an electron. This can be explained using the valence electrons and how many need to be added or removed to complete the octet. The further right you are, the easier it is for the element to just gain a few electrons instead of loose a bunch. Noble gases are the exception to this since they don't normally react though.
