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monitta
3 years ago
14

Oxidation elements of the numbers H2CO2

Chemistry
1 answer:
yawa3891 [41]3 years ago
8 0
Carbon atoms oxidation number is +2.Hydrogen's oxidation number is +1.Oxygen's oxidation number is -2.
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If an atom of sodium has 11 protons, what is its approximate atomic mass?
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Answer both questions
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I need help with chemistry
Leona [35]

Hey there!

Your answer is B. MgCl.

This is because this isn't an actual existing compound.

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Hope this helps!

6 0
3 years ago
What is the product of silver nitrate + lead ii nitrate?
Kisachek [45]

Answer:

Explanation:

In theory, not much of anything. The vast majority of nitrates are water soluble. Aside, not sure what chemistry level you are at but you will probably be asked to know or memorize some solubility rules. This, for lack of a better phrase, Nitrate rule, is near spot on. With one exception—a rare one—all metal cationic nitrates are soluble in water. All of them. So, assuming you are talking about aqueous, water-based solutions of these salts and mixing them together, I expect nothing to occur. Both solutions, I believe are colorless in water and will thus remain so. If you had say a solution of Iron (III) nitrate and copper (II) nitrate, slightly different story. Both are colorful solutions and I would think you might see blending of colors but no reaction; no precipitate will form. You will probably learn about markers of a chemical reaction. One of these is a color change. Note, you should read this as a change of color from what you previously had. Going from red to blue or colorless to colored (or vice versa) is a strong indication of a reaction (e. g. evidence of bond-breaking and bond-formation). The mere mixing of colors does not constitute a chemical reaction.

3 0
3 years ago
Calculate the minimum concentration of Mg2+ that mustbe added to 0.10 M NaF in order to initiate a precipitate ofmagnesium fluor
blondinia [14]

Answer:

E. 6.9 E-7 M

Explanation:

  • NaF  →  Na+   +     F-

      0.10M   0.10M    0.10M

  • MgF2 ↔ Mg2+  +    2F-

eq:     S             S          2S + 0.1

∴ Ksp = 6.9 E-9 = [Mg2+][F-]² = (S)(2S+0.1)²

if we compared the concentration ( 0.1 M ) with the Ksp ( 6.9 E-9 ); then we can neglect the solubility as adding:

⇒ Ksp = 6.9 E-9 = (S)(0.1)² = 0.01S

⇒ S = 6.9 E-9 / 0.01 = 6.9 E-7 M

6 0
3 years ago
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