Answer:
1 km * 1000 m / km * 100 cm / m = 10^5 cm / km
V = 4 / 3 pi R^3
V = 4 / 3 * pi * (7.01 * 10^5 * 10^5)^3 = 4 / 3 pi * 344 * (10^10)^3
V = 1.443^10^3 * 10^30 = 1.44 10^33cm^3
We have that every gas satisfies the fundamental gas equation, PV=nRT where P is the Pressure, V is the volume of the gas, n are the moles of the gas, R is a universal constant and T is the Temperature in Kelvin. We have that PV/T=nR and during our process, the moles of the gas do not change (no argon enters or escapes our sample). See attached.
Hiii,so the problem is ♀️
C. 28 KJ
AMU of H2O2 = 2(1) + 2(16) = 34 g/mol
10 g / 34 g/mol = 0.294 mol H2O2
0.294 mol / H = 2 mol / 190 KJ
H = 28.9 KJ