Answer : The freezing depression of a solution is
Explanation : Given,
Molal-freezing-point-depression constant for water =
Mass of glycerin (solute) = 30.7 g
Volume of water (solvent) = 376 mL
Molar mass of glycerin = 92.09 g/mole
First we have to calculate the mass of water.
As we know that, the density of water is 1.0 g/mL.
So, mass of water = Density of water × Volume of water
Mass of water = 1.0 g/mL × 376 mL
Mass of water = 376 g = 0.376 kg (1 g = 0.001 kg)
Now we have to calculate the freezing point depression of a solution.
Formula used :
where,
= change in freezing point
= freezing point of solution = ?
= freezing point of water =
i = Van't Hoff factor = 1 (for glycerin non-electrolyte)
= freezing point constant for water =
m = molality
Now put all the given values in this formula, we get
Therefore, the freezing depression of a solution is