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3 years ago

Which method involves separating a solution by liquids moving across a selectively permeable membrane?

Chemistry

2 answers:

Kisachek [45]3 years ago

7 0

Answer:

OSMOSIS

Explanation:

Osmosis (/ɒzˈmoʊ.sɪs/) is the spontaneous net movement or diffusion of solvent molecules through a selectively permeable membrane from a region of high water potential (region of lower solute concentration) to a region of low water potential (region of higher solute concentration),

koban [17]3 years ago

4 0

Osmosis is the correct answer d

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Which statement holds true when the molar mass of hydrogen is 2.0 grams and that of helium is 4.0 grams?

ehidna [41]

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3 years ago

Which bent shape has more repulsion and a smaller bond angle? bent 6A bent 5A

Step2247 [10]

Bent 6A is the answer

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3 years ago

Determine the compound type for the following formulas: C12H22011 Mg(OH)2 H20 Cu3Zn2 Au

Scorpion4ik [409]

Answer:

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Mg(OH)2

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Explanation:

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3 years ago

Read 2 more answers

Which of the following bases can remove a proton from formic acid in a reaction that favors products?

Debora [2.8K]

Hydroxide ion is a strong and would react with H+ to form water

OH-+H+---->H2O

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3 years ago

A sample of N2 gas in a flask is heated from 27 Celcius to 150 Celcius. If the original gas is @ pressure of 1520 torr, what is

Romashka [77]

Answer:

$\large \boxed{\text{B.) 2.8 atm}}$

Explanation:

The volume and amount are constant, so we can use Gay-Lussac’s Law:

At constant volume, the pressure exerted by a gas is directly proportional to its temperature.

$\dfrac{p_{1}}{T_{1}} = \dfrac{p_{2}}{T_{2}}$

Data:

p₁ = 1520 Torr; T₁ = 27 °C

p₂ = ?; T₂ = 150 °C

Calculations:

(a) Convert the temperatures to kelvins

T₁ = ( 27 + 273.15) K = 300.15 K

T₂ = (150 + 273.15) K = 423.15 K

(b) Calculate the new pressure

$\begin{array}{rcl}\dfrac{1520}{300.15} & = & \dfrac{p_{2}}{423.15}\\\\5.064 & = & \dfrac{p_{2}}{423.15}\\\\5.064\times423.15&=&p_{2}\\p_{2} & = & \text{2143 Torr}\end{array}\\$

(c) Convert the pressure to atmospheres

$p = \text{2143 Torr} \times \dfrac{\text{1 atm}}{\text{760 Torr}} = \textbf{2.8 atm}\\\\\text{The new pressure reading will be $\large \boxed{\textbf{2.8 atm}}$}$

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3 years ago