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3 years ago

15

Please help!

2 answers:

Arturiano [62]3 years ago

8 0

Answer:

D on edg

Step-by-step explanation:

just did the quiz

Cerrena [4.2K]3 years ago

4 0

Answer:

D: The function has a hole when x = 3, and vertical asymptotes when x = 0 and x = 5.

Step-by-step explanation:

The given rational function has vertical asymptotes and holes. Remember that an asymptote is placed when the function has undetermined results, when we give a x-value and the y-value cannot be determined, there we say exists an asymptotes, which is a punctual line that represents a discontinuation of the graph, the trace cannot cross that asymptote, it divide the whole function graph.

So, in this case we have to undetermined results when the function has a hole of x = 3, and vertical asymptotes when x = 0 and x = 5.

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3 years ago

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lapo4ka [179]

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OlgaM077 [116]

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3 years ago

Write the equation for a 3rd degree polynomial function that has roots at x = 1–3i and x = 2. The y‑intercept is (0,10). Write a

HACTEHA [7]

Answer:

$\displaystyle P(x)=-\frac{1}{2}(x^2+2x+10)(x-2)$

Step-by-step explanation:

<u>Factored Form Of Polynomials </u>

If we know the roots of a polynomial as

$\alpha _1,\alpha _2,\alpha _3$

the polynomial can be expressed in factored form as

$a(x-\alpha _1)(x-\alpha _2)(x-\alpha _3)$

We are given two of the three roots of the polynomial:

$\alpha _1=1-3i$

$\alpha _2=2$

The other root must be the conjugate of the complex root:

$\alpha _3=1+3i$

Recall the product of two complex conjugate numbers is

$(1-3i)(1+3i)=1^2-(3i)^2=1+9=10$

The required polynomial is

$P(x)=a\left[ x-(1-3i)\right ]\left[ x-(1+3i)\right ](x-2)$

$P(x)=a(x^2+2x+10)(x-2)$

This is the factored form of the polynomial where only real numbers appear

We need to find the value of a, such as

$P(0)=10$

$P(0)=a(0^2+2(0)+10)(0-2)=10$

$-20a=10$

Thus the value of a is

$\displaystyle a=-\frac{1}{2}$

The expression of the required polynomial is

$\boxed{P(x)=-\frac{1}{2}(x^2+2x+10)(x-2)}$

5 0

3 years ago

2. Evaluate the expression -4r +5 y-14<br> when r = 0 and y=-<br> 55

Alecsey [184]

Answer:

Answer is 261

Step-by-step explanation:

-4r+5y-14 r=0 y=55

insert "r" and "y" values into equation

=-4(0)+5(55)-14

evaluate;

-4(0)=0

5(55)=275

so, now the equation would look like this;

=275-14

<h2>=261</h2>

3 0

3 years ago