2. A stone is thrown upwards with an initial velocity of 25 m/s at

What happens to the chemical structure of water when it changes state?

Marta_Voda [28]

Answer:

c) Water molecules melt into gas molecules.

5 0

3 years ago

For this problem, imagine that you are on a ship that is oscillating up and down on a rough sea. Assume for simplicity that this

ikadub [295]

Answer:

no idea

Explanation:

7 0

4 years ago

In the diagram, the arrow shows the movement of electric charges through a wire connected to a battery.

solong [7]

Due to difference in electric potential.

<h3>What is Potential difference?</h3>

The amount of work in an electrical field to move a unit charge from one place to another is known as the electrical potential difference.

Here , the potential difference is the difference in electric potential between two charged substances.

Current is the flow of charges from one end end to another end of a conducting wire connected across a two terminals of a battery.

The potential difference is [provided by the battery across the two terminals due which the charges flow.

Current flow is from positive to negative terminals, indicating the movement of positive charges in that direction.

Hence , potential difference causes the electric charges to flow from one end of the battery .

Learn more about the flow of current : brainly.com/question/2264542

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6 0

2 years ago

g A ball thrown straight up into the air is found to be moving at 7.94 m/s after falling 2.72 m below its release point. Find th

kati45 [8]

The ball has height y and velocity v at time t according to

y = v₀ t - 1/2 g t ²

and

v = v₀ - g t

where v₀ is its initial speed and g = 9.80 m/s² is the magnitude of the acceleration due to gravity.

The ball is falling with a velocity of 7.94 m/s when it's 2.72 m below the release point, which at time t such that

-2.72 m = v₀ t - 1/2 g t ²

-7.94 m/s = v₀ - g t

Solve for t in the second equation:

t = (v₀ + 7.94 m/s)/g

Substitute this into the first equation and solve for v₀ :

-2.72 m = v₀ (v₀ + 7.94 m/s) /g - 1/2 g ((v₀ + 7.94 m/s)/g)²

-2.72 m = v₀²/g + (7.94 m/s) v₀/g - 1/2 (v₀ + 7.94 m/s)²/g

2 (-2.72 m) g = 2v₀² + 2 (7.94 m/s) v₀ - (v₀ + 7.94 m/s)²

2 (-2.72 m) (9.80 m/s²) = 2v₀² + (15.9 m/s) v₀ - (v₀² + (15.9 m/s) v₀ + 63.0 m²/s²)

-53.3 m²/s² = v₀² - 63.0 m²/s²

v₀² = 9.73 m²/s²

v₀ = 3.12 m/s

3 0

3 years ago

A block of mass 57.1 kg rests on a slope having an angle of elevation of 28.3°. If pushing downhill on the block with a force ju

stira [4]

Answer:

The coefficient is 0.90

Explanation:

Drawing a diagram makes thing easier, we will assume that the acceleration tends to zero because it start barely moving.

$-F_s+mg*sin(\theta)+F=0\\F_s=57.1kg*9.8m/s^2*sin(28.3)+177N\\F_s=442N\\F_s=\µ*N\\N=m*g*cos(\theta)\\N=57.1*9.8*cos(28.3)=493N\\\\\µ=\frac{442N}{493N}=0.90$

3 0

3 years ago