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Shkiper50 [21]
3 years ago
13

The harder I push an object the _______ it will travel.

Physics
2 answers:
lions [1.4K]3 years ago
8 0

It's b, because the more force an object it is given the harder it will be for it to slow down.

STatiana [176]3 years ago
3 0
The answer is b because it’s b
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disa [49]

It makes calculations with very large and small numbers easier.

Scientific notation is a system used in order to It makes calculations with very large and small numbers easier. It is useful as it allows very large number that would take a lot of space to write otherwise, and it allows them to be calculated easier. 10^{23} for example is a incredible large number, but written in this form is immediately understandable and useful for calculation.

3 0
3 years ago
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245289457u2895785/+55891235723895718957=
Bingel [31]

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6 0
2 years ago
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Please help!?!?!?!?!?!?!
adoni [48]

Answer:

D

Explanation:i think but dont get mad if im wrong

5 0
2 years ago
HeLp AsAp!!!!!! How long would it take you to hop 30 meters based on your speed for the 5-meter trial? Show your work!
Novosadov [1.4K]

Answer:

20.5s

Explanation:

Given parameters:

Distance = 30m

Unknown:

Time  = ?

Solution:

The time it will take to hop a distance of 30m using the speed for the 5m trial is the duration of the trip.

 The speed for the 5m trial  = 1.46m/s

Now;

    Speed  = \frac{distance}{time}

      Distance = speed x time

      time  = \frac{distance }{speed}

Input the parameters and solve;

     time  = \frac{30}{1.46}   = 20.5s

7 0
3 years ago
Suppose that 2 J of work are needed to stretch a spring from its natural length of 30 cm to a length of 42 cm. How far (in cm) b
sergeinik [125]

A distance of 10.8 cm beyond its natural length will a force of 30 N keep this spring stretched

<u>Explanation:</u>

Work, W = 2 J

Initial distance, x_{1} = 30 cm

Final distance,  = 42 cm

Force, F = 30 N

Stretched length, x = ?

We know,

W = 1/2 kΔx²

Δx = 42-30 cm = 12 cm = 0.12 m

2 J = 1/2 k X (0.12)²

k = 277.77 N/m

According to Hooke's law,

F = kx

30 N = 277.77 X x

x = 0.108 m

x = 10.8  cm

A distance of 10.8 cm beyond its natural length will a force of 30 N keep this spring stretched.

7 0
2 years ago
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