How many significant figures are there in 0.0000303?
1 answer:
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The correct answer is:
<span>The rate at which a waves energy flows through a given unit of area
In fact, light intensity is defined as the light power per unit of area:
</span>
<span>but the power is the energy carried by the light per unit of time:
</span>
<span>this means that the intensity can be rewritten as
</span>
<span>
So, it's basically the rate of energy (per unit of time) through a given surface.</span>
<span>The rate at which a waves energy flows through a given unit of area
In fact, light intensity is defined as the light power per unit of area:
</span>
<span>but the power is the energy carried by the light per unit of time:
</span>
<span>this means that the intensity can be rewritten as
</span>
So, it's basically the rate of energy (per unit of time) through a given surface.</span>
Answer:
E = 1.04*10⁻¹ N/C
Explanation:
Assuming no other forces acting on the proton than the electric field, as this is uniform, we can calculate the acceleration of the proton, with the following kinematic equation:
As the proton is coming at rest after travelling 0.200 m to the right, vf = 0, and x = 0.200 m.
Replacing this values in the equation above, we can solve for a, as follows:
According to Newton´s 2nd Law, and applying the definition of an electric field, we can say the following:
F = mp*a = q*E
For a proton, we have the following values:
mp = 1.67*10⁻²⁷ kg
q = e = 1.6*10⁻¹⁹ C
So, we can solve for E (in magnitude) , as follows:
⇒ E = 1.04*10⁻¹ N/C
Complete Question
The diagram for this question is shown on the first uploaded image
Answer:
The minimum velocity of A is
Explanation:
From the question we are told that
The length of the string is
The initial speed of block A is
The final speed of block A is
The initial speed of block B is
The mass of block A is gh
The mass of block B is
According to the principle of conservation of momentum
Since block B at initial is at rest
making the subject of the formula
Substituting values
This is the velocity at bottom of the vertical circle just at the collision with mass A
Assuming that block B is swing through the vertical circle(shown on the second uploaded image ) with an angular velocity of at the top of the vertical circle
The angular centripetal acceleration would be mathematically represented
Note that this acceleration would be toward the center of the circle
Now the forces acting at the top of the circle can be represented mathematically as
Where T is the tension on the string
According to the law of energy conservation
The energy at bottom of the vertical circle = The energy at the top of
the vertical circle
This can be mathematically represented as
From above
Substitute this into above equation
The value of velocity of block A needed to cause B be to swing through a complete vertical circle is would be minimum when tension on the string due to the weight of B is zero
This is mathematically represented as
making the subject
substituting values
