Consider the charge for parking one car for t hours.
If t is more than 1, then the function is y=3+2(t-1), because 3 $ are payed for the first hour, then for t-1 of the left hours, we pay 2 $.
If t is one, then the rule y=3+2(t-1) still calculates the charge of 3 $, because substituting t with one in the formula yields 3.
75% is 75/100 or 0.75.
For whatever number of hours t, the charge for the first car is 3+2(t-1) $, and whatever that expression is, the price for the second car and third car will be
0.75 times 3+2(t-1). Thus, the charge for the 3 cars is given by:
3+2(t-1)+0.75[3+2(t-1)]+0.75[3+2(t-1)]=3+2(t-1)+<span>0.75 × 2[3 + 2(t − 1)].
Thus, the function which total parking charge of parking 3 cars for t hours is:
</span><span>f(t) = (3 + 2(t − 1)) + 0.75 × 2(3 + 2(t − 1))
Answer: C</span>
Answer:
all work is shown and pictured
Answer:
57 cm²
Step-by-step explanation:
Surface area of the yellow prism = front + back + right + left + top
✔️Area of the front = L * W
L = 4 cm
W = 3 cm
Area of the front = 4*3 = 12 cm²
✔️Area of the back = L * W
L = 4 cm
W = 3 cm
Area of the back = 4*3 = 12 cm²
✔️Area of the right face = L * W
L = 4 cm
W = 3 cm
Area of the right face = 4*3 = 12 cm²
✔️Area of the left face = L * W
L = 4 cm
W = 3 cm
Area of the left face = 4*3 = 12 cm²
✔️Area of the top = L * W
L = 3 cm
W = 3 cm
Area of the top = 3*3 = 9 cm²
✅Total = 12 + 12 + 12 + 12 + 9 = 57 cm²
Answer:
(3x-1) (3x+1)
Step-by-step explanation:
9x^2-1
Rewriting as
(3x)^2 - 1^2
This is the difference of squares
a^2 - b^2 = (a-b)(a+b)
(3x-1) (3x+1)
They are up and down and left and right
