Answer:
1. -4
2. 6
3. -6
(i hope this is right •_•)
Step-by-step explanation:
<u>First table</u>
When the x coordinate is 0, that point is your y intercept. For the first one, your y intercept is -4.
<u>Second table</u>
For the second one, we need to do a bit of counting. We can see the x coordinates go before and after zero, but the table does not show us 0. So, we're going to have to calculate the slope. Bear with me here, I'm a little tired and this might be rambling ;-;
So, the formula for calculating slope is
. I'm going to use those first two points to get my slope. We're going to say the first point is point 1 and the second point is point 2 (genius, i know lol). So, let's substitute in the x and y values.

And simplify...

So, your slope is -1. We can use that. We just have to count down.
If the x is -2, the y is 8. If the x is -1, the y is 7. And if the x is 0....(drumroll please) the y is 6! So, your y intercept is 6.
<u>Third table</u>
Now, this table isn't very nice either and doesn't have an x as 0 for us. Hmpf. But we can still do what we did above. I'll just skip the explanation and you can observe my steps.



Let's count down....
If x = 3, y = -5
If x = 2, y = -5 1/3
If x = 1, y = -5 2/3
If x = 0, y = -6
The square is 12 m long and the triangle is 11 m long
Answer:
0.06
Step-by-step explanation:
I can't see pictures, but to find the area of a triangle, you multiply the dimensions, as you would a rectangle, but divide the area by 2.
For example, the dimensions of a triangle are 4 and 6.
Multiply the two.
4x6=24.
But don't stop there. Divide 24 by 2.
24/2=12.
So the area of the example triangle is 12.
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hope it helps
1)
2x-y=16
-2y-x=-8
You need to solve on of the equations for x or y. I will solve the first equation for y.
2x-y=16
-y=-2x+16
y=+2x-16
Then you can substitute that y value for the y value in the second equation (2y-x=-8) can be written as 2(2x-16)-x=-8 since y=2x-16.
then you solve for x.
4x-32-x=-8
3x=24
x=8
therefore y=0 since 2(0)-8=-8
I will complete the second part of the question either in the comments or a new answer later when I have more time.