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salantis [7]
4 years ago
12

How has sir isaac newton contributed to our understanding of forces

Physics
1 answer:
Nitella [24]4 years ago
8 0
<span>Sir Isaac Newton discovered many scientific wonders.

- </span>Sir Isaac Newton contributed to our understanding of forces by <span>formulating  the </span>Laws<span> of Motion and also </span>Law<span> of Universal Gravitation.

Hope this helps</span>
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3. An engine’s fuel is heated to 2,000 K and the surrounding air is 300 K. Calculate the ideal efficiency of the engine. Hint: T
maksim [4K]

Answer: E = 0.85

Therefore the efficiency is: E = 0.85 or 85%

Explanation:

The efficiency (e) of a Carnot engine is defined as the ratio of the work (W) done by the engine to the input heat QH

E = W/QH.

W=QH – QC,

Where Qc is the output heat.

That is,

E=1 - Qc/QH

E =1 - Tc/TH

where Tc for a temperature of the cold reservoir and TH for a temperature of the hot reservoir.

Note: The unit of temperature must be in Kelvin.

Tc = 300K

TH = 2000K

Substituting the values of E, we have;

E = 1 - 300K/2000K

E = 1 - 0.15

E = 0.85

Therefore the efficiency is: E = 0.85 or 85%

4 0
4 years ago
I dont understand how to find the blanks​
Amiraneli [1.4K]

The forces are:

F_{grav} = 98,000 N, down

F_{net} = 80,000 N, down

F_{air}=18,000 N, up

Explanation:

We start by finding the force of gravity on the elephant, F_{grav}, which is given by

F_{grav}=mg (downward)

where

m = 10,000 kg is the mass of the elephant

g=9.8 m/s^2 is the acceleration of gravity

Substituting,

F_{grav}=(10,000)(9.8)=98,000 N

Now we know that the net acceleration of the elephant is

a_{net}=8.0 m/s^2 downward

We can now use Newton's second law:

F_{net}=ma_{net}

where F_{net} is the net force on the elephant. Substituting, we find

F_{net}=(10,000)(8.0)=80,000 N

and it also acts downward, since it has the same direction as the acceleration.

Finally, we can write the net force on the elephant as

F_{net}=F_{grav}-F_{air}

where the force of gravity acts downward, while the air resistance (F_{air} acts upward. The net force also acts downward, so it has the same sign of gravity.

Substituting:

F_{net}=80,000 N\\F_{grav}=98,000 N

And solving, we find the air resistance:

F_{air}=F_{grav}-F_{net}=98,000-80,000 = 18,000 N (upward)

Learn more about forces and Newton laws of motion:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

4 0
4 years ago
Important nuclei of the indirect (multineuronal) system that receive impulses from the equilibrium apparatus of the inner ear an
Lera25 [3.4K]

Answer:

B. Vestibular nuclei

Explanation:

The nerve information generated by the vestibular receptors travels through the vestibular portion of the eighth pair that penetrates the brain stem at the level of the brain stem bridge. At this level there are four vestibular nuclei, which receive the synapses of these axons, coming from the ridges and macules. The semicircular ducts predominantly terminate in the superior and medial nuclei. While the fibers coming from the macules end on the lateral, medial and inferior nuclei. Some fibers of the eighth pair end in the flocculonodular lobe of the cerebellum, <u>these connections play an important role in controlling posture and balance.</u>

From the vestibular nuclei, two bundles of fibers descending to the spinal cord originate from the medial and lateral vestibular spinal bundles and a bundle of fiber that rises in the brain stem that participates in the coordination of eye movements, the medial longitudinal fascicle, which participates in Rotational nystagmus This system also participates in an important way in the control of some ocular movements by the fibers that it contributes to the medial longitudinal fascicle, which is a structure that interconnects the motor nuclei of the extrinsic muscles of the eyeballs VI or abdicens nucleus (abductor) on one side and IV or pathetic nucleus (trochlear) and III or nucleus of the common ocular motor (oculomotor) on the opposite side.

6 0
3 years ago
Imagine whirling a ball on a string over you head. Suppose the knot holding the ball comes loose and the ball is instantly relea
zaharov [31]

B is the answer to the question

8 0
3 years ago
A man pulls a wagon with a handle that is at an angle of 42° with the ground. If the man pulls with 330 N of force, how much for
Fed [463]

Answer:

245N

Explanation:

We just need to multiply the force the man pulls the wagon by the cosine of the angle with the ground.

F = 330N * cos(42°) = 245.2N

8 0
4 years ago
Read 2 more answers
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