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4 years ago

12

How has sir isaac newton contributed to our understanding of forces

1 answer:

Nitella [24]4 years ago

8 0

<span>Sir Isaac Newton discovered many scientific wonders.

- </span>Sir Isaac Newton contributed to our understanding of forces by <span>formulating the </span>Laws<span> of Motion and also </span>Law<span> of Universal Gravitation.

Hope this helps</span>

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qaws [65]

Answer:

$r = 2.84 \times 10^{-14} m$

Explanation:

As per energy conservation we know that the electrostatic potential energy of the charge system is equal to the initial kinetic energy of the alpha particle

So here we can write it as

$\frac{1}{2}mv^2 = \frac{k(2e)(ze)}{r}$

now we know that

$m = 1.67 \times 10^{-27} kg$

$e = 1.6 \times 10^{-19} C$

z = 79

here kinetic energy of the incident alpha particle is given as

$KE = 6.4 \times 10^{-13} J$

now we have

$6.4 \times 10^{-13} = \frac{(9\times 10^9)(1.6 \times 10^{-19})^2(79)}{r}$

now we have

$r = 2.84 \times 10^{-14} m$

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if a weight of 100 lbs is moved through a displacement of 1.2m, how much work was done to move the weight

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2 years ago

Alcohol of mass 21g and density 0.7gcm-3 is mixed with 10g of water. Determine the density

IRINA_888 [86]

Answer:

0.775 g/cm³

Explanation:

The given parameters are;

The mass of the alcohol = 21 g

The density of the of the alcohol = 0.7 g/cm³

The mass of water with whichit is mixed = 10 g

The density of water = 1.0 g/cm³

Therefore, the mass of the mixture, m = 21 g + 10 g = 31 g

Volume = Mass/Density

The volume of the alcohol = 21 g/(0.7 g/cm³) = 30 cm³

The volume of the water = 10 g/(1.0 g/cm³) = 10 cm³

Therefore, the volume of the mixture, V = 30 cm³ + 10 cm³ = 40 cm³

The density of the mixture, ρ = (Mass, m)/(Volume, V) = m/V

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The density of the mixture, ρ = 0.775 g/cm³.

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3 years ago