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Let's see
Now we know the formula of acceleration
Or
The mass on the left has a downslope weight of
W1 = 3.5kg * 9.8m/s² * sin35º = 19.7 N
The mass on the right has a downslope weight of
W2 = 8kg * 9.8m/s² * sin35º = 45.0 N
The net is 25.3 N pulling downslope to the right.
(a) Therefore we need 25.3 N of friction force.
Ff = 25.3 N = µ(m1 + m2)gcosΘ = µ * 11.5kg * 9.8m/s² * cos35º
25.3N = µ * 92.3 N
µ = 0.274
(b) total mass is 11.5 kg, and the net force is 25.3 N, so
acceleration a = F / m = 25.3N / 11.5kg = 2.2 m/s²
tension T = 8kg * (9.8sin35 - 2.2)m/s² = 27 N
Check: T = 3.5kg * (9.8sin35 + 2.2)m/s² = 27 N √
hope this helps. :)
Answer: v= 330m/s
Explanation: the length (l) of an open closed pipe is related to the wavelength (λ) as shown in the formulae below
l = λ/4
where l = 0.55m, hence we have that
0.55 = λ/4
λ = 0.55*4
λ = 2.2m
from the question, it can be seen that the fundamental frequency is 150Hz.
Recall that we have v=fλ, where v = speed of wave, f= frequency, λ= wavelength
v =2.2 * 150
v = 330 m/s
