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lilavasa [31]
3 years ago
9

g A small object of mass 2.5 g and charge 18 uC is suspended motionless above the ground when immersed in a uniform electric fie

ld perpendicular to the ground. What is the magnitude and direction of the electric field
Physics
1 answer:
kvasek [131]3 years ago
4 0

Answer: 1361.11\ N/C,\text{upward}

Explanation:

Given

Mass of particle is m=2.5\ gm

Charge of particle is q=18\ \mu C

Electrostatic force must balance the weight of the particle

\lim_{n \to \infty} a_n \Rightarrow mg=qE\\\\\Rightarrow E=\dfrac{2.5\times 9.8\times 10^{-3}}{18\times 10^{-6}}\\\\\Rightarrow E=1361.1\ N/C

Direction of the electric field is in upward direction such that it opposes the gravity force.

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