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3 years ago

13

(hurry pls)Carl plugs in a lamp that has 0.67 of resistance and 8.1 volts running through it. What is the amount of current runn

ing through the lamp? C 543 A C 0.08 A C 12.09 A C743 A

1 answer:

Mazyrski [523]3 years ago

5 0

Answer:

C)12.09 Ampere

Explanation:

V= IR

Where I= current of the system

R= resistance= 0.67 ohm

V= potential difference=8.1 volts

Substitute the values

8.1= I× 0.67

I= 8.1/0.67

=12.09 Ampere

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<em>ANSWER</em>

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$6.02\cdot10^{23}$ $\begin{gathered} 5.45\cdot10^{26}\text{ = x }\cdot\text{ 6.02 }\cdot10^{23} \\ \text{Divide both sides by 6.02 }\cdot10^{23} \\ x\text{ = }\frac{5.45\cdot10^{26}}{6.02\cdot10^{23}} \\ x\text{ = }\frac{5.45}{6.02}\cdot10^{26\text{ - 23}} \\ x\text{ = 0.9053 }\cdot10^3 \\ x\text{ = 905.32 moles} \end{gathered}$

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