Answer:
the amount of valence electron, cna be found in the periodic table, which is called the atomic number which is top of the symbol
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The product of the complete combustion of any fuel (in this case, acetylene) are indeed water and carbon dioxide.
Balancing the combustion reaction,
C2H2 +(5/2) O2 --> 2CO2 + H2O
The number of moles of C2H2 will be,
(12 g) x (1 mole/26 g) = 6/13 mole
Then, the number of moles of O2 is,
(12 g) x (1 mole/32 g) = 3/8 mole
Therefore the limiting reaction is the O2. Getting the amount of CO2 and H2O produced from balancing,
CO2 = (3/8 moles) x (2 moles CO2/ 5/2 mole O2)(44 g/ 1 mole) = 52.8 g
H2O = (3/8 moles) x (1 mole / 5/2 mole O2)(18 g / 1 mole) = 2.7 g
(the heat bomb calorimeter gained)=(the heat material A gave)
r.h.s=25.57 kJ/⁰C * (26.80-24.33)= 63.16 kJ
2.741g of material A made 63.16kJ
the heat of combustion per gram = 63.16/2.741 kJ/g =24.04kJ/g
Answer:
PH₂ = 0.2 atm
C) About 0.20atm, because H2 comprises 20% of the total number of moles of gas.
Explanation:
To determine the partial pressure of hydrogen gas (H2) in the mixture,
Partial pressure H₂ = Ptotal * xH₂
xH₂ = Mole fraction of H₂ = ∩H₂ / ( ∩H₂ + ∩O₂ + ∩N₂)
xH₂ = 0.01 / (0.01 + 0.015 + 0.025)
xH₂ = 0.01/0.05
xH₂ = 0.2
therefore
PH₂ = pT * xH₂
PH₂ = 1.0 atm * 0.2
PH₂ = 0.2 atm
so the correct option is C) About 0.20atm, because H2 comprises 20% of the total number of moles of gas.
Answer:
doppler radar, radiosondes, weather satellites, buoys
