All categories

2 years ago

This questions pls help

Physics

2 answers:

abruzzese [7]2 years ago

7 0

Answer:

1. True

2. False

3. True

4. True

5. False

qaws [65]2 years ago

3 0

True, False, True, True, False :) !

You might be interested in

A scientist who studies teenage behavior was interested in determining if teenagers spend more time playing computer games then

natita [175]

Answer:

greater than 0.10

Explanation:

The null hypothesis is:

$H_{0} = 10.2$

The alternate hypotesis is:

$H_{1} > 10.2$

Our test statistic is:

$t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the statistic, $\mu$ is the mean, $\sigma$ is the standard deviation and n is the size of the sample.

We have that:

$t = 0.45$

We are testing if X is greater than 0.45, so our pvalue is 1 subtracted by the pvalue of z = t = 0.45.

z = 0.45 has a pvalue of 0.6736

1 - 0.6735 = 0.3264

So our pvalue is 0.3264, which is greater than 0.10.

So the correct answer is:

greater than 0.10

7 0

3 years ago

Create a group of 3-4 students. Using your cell phone flashlight and the filter, create a "blue" flashlight, "red" flashlight, a

Korvikt [17]

Answer:

the light creates sorta a mixture of all the colors on the white index card.

4 0

3 years ago

A plane leaves with an acceleration of 6.34 m/s squared and takes 1.5 hours to stop. What is the speed of the plane? What was th

Maurinko [17]

The answer to this question is Initial velocity of plane will be 34236 m/s and 92437.2 Km is the distance travelled by it.

Three equation of motion are:-

v = u + at
s = ut + (1/2)at²
v² - u² = 2as

Where v is final velocity, u in initial velocity, s is the displacement by the object, a is the acceleration and t denotes the time.

In question we have given deceleration as 6.34 m/s² and time as 1.5 hour which is equal to 5400 seconds.

Applying equation 1 to find the initial speed of plane

v = u + at

0 = u + (-6.34 × 5400) {v=0 as plane will stop after 5400 sec}

u = 6.34 × 5400

u = 34236 m/s

Initial velocity of plane is 34236 m/s

Applying equation 2 to find the displacement of plane in that time period

s = ut + (1/2)at²

s = ( 34236 × 5400 ) - ( (1/2) × 6.34 × 5400² )

s = 5400 × ( 34236 - ((1/2) × 6.34 × 5400) )

s = 5400 × ( 34236 - 17118 )

s = 5400 × 17118 metres

s = 5.4 × 17118 Km

s = 92437.2 Km

Distance travelled by plane is 92437.2 Km

So, the initial velocity of plane will be 34236 m/s and the displacement of plane in that time period will be 92437.2 Km.

Learn more about Motion here:

brainly.com/question/25951773

#SPJ10

3 0

2 years ago

A 20-cm-long stick of m = 0.600 kg is lifted by a rope tied 5.0 cm from the upper end. The other end touches a smooth floor. The

Liula [17]

Answer:

https://www.chegg.com/homework-help/questions-and-answers/part-20-cm-long-stick-m-0400-kg-lifted-rope-tied-70-cm-upper-end-end-touches-smooth-floor--q81268572

3 0

2 years ago

Metric conversions

sergij07 [2.7K]

1:-

1L=1000mL

$\\ \sf\longmapsto 45.23L$

$\\ \sf\longmapsto 45.23\times 1000$

$\\ \sf\longmapsto 45230mL$

2:-

1hL=10000cL

$\\ \sf\longmapsto .035hL$

$\\ \sf\longmapsto 0.035\times 10000$

$\\ \sf\longmapsto 350cL$

3:-

1mm=0.0001m

$\\ \sf\longmapsto 27.32$

$\\ \sf\longmapsto 27.32\times 0.0001$

$\\ \sf\longmapsto 0.0027m$

7 0

3 years ago