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yawa3891 [41]
3 years ago
7

**HELP ASAP**

Physics
1 answer:
Tcecarenko [31]3 years ago
5 0
The answer of this question is B.
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If two firecrackers produce a sound level of 81 dBdB when fired simultaneously at a certain place, what will be the sound level
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Answer:

77.96dB

Explanation:

Recall that decibels are a unit of measuring intensity of sound, and depend on the logarithm of the intensity

the intensity, measured in decibels is given by:

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I is the intensity in MKS units; I0 is the threshold intensity for human hearing (10^-12 W/m^2)

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therefore, one firecracker has an intensity half of that, or 0.0000625W/m^2

now use this value to find the dB of one firecracker:

I(dB0=10log(0.0000625/10^-12)=77.96dB

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