<span>1.7 rad/s
The key thing here is conservation of angular momentum. The system as a whole will retain the same angular momentum. The initial velocity is 1.7 rad/s. As the person walks closer to the center of the spinning disk, the speed will increase. But I'm not going to bother calculating by how much. Just remember the speed will increase. And then as the person walks back out to the rim to the same distance that the person originally started, the speed will decrease. But during the entire walk, the total angular momentum remained constant. And since the initial mass distribution matches the final mass distribution, the final angular speed will match the initial angular speed.</span>
Answer:
Explanation:
speed of alien spaceship = .1 c
We shall apply formula of relativistic mechanics to solve the problem
relative velocity =
Here v = v₁ = .1 c
relative velocity = .1c + .1 c / 1 - .1²
= .2 c / .99
= .202 c
The earth would receive the signal at the speed of .202 c .
It is 5.3 x 10^-9 kiloliters.
Hope this helps.
Answer:
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Explanation:
Answer:
B. 3 m/s
Explanation:
We can solve the problem by using the law of conservation of momentum; in fact, the total momentum before and after the collision must be conserved. So we can write:
![m_1 u_1 + m_2 u_2 = (m_1 +m_2)v](https://tex.z-dn.net/?f=m_1%20u_1%20%2B%20m_2%20u_2%20%3D%20%28m_1%20%2Bm_2%29v)
where:
m1 = 150 kg is the mass of spaceship 1
m2 = 150 kg is the mass of spaceship 2
u1 = 0 m/s is the initial velocity of spaceship 1
u2 = 6 m/s is the initial velocity of spaceship 2
v is the velocity of the two ships after they collide and stick together
Solving for v, we find:
![v=\frac{m_1 u_1 + m_2 u_2}{m_1+m_2}=\frac{0+(150)(6)}{150+150}=3 m/s](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bm_1%20u_1%20%2B%20m_2%20u_2%7D%7Bm_1%2Bm_2%7D%3D%5Cfrac%7B0%2B%28150%29%286%29%7D%7B150%2B150%7D%3D3%20m%2Fs)