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4 years ago

Help please!!!!!!!!!!!!!!!!!!!!

Physics

1 answer:

Pavel [41]4 years ago

8 0

Looks like you need to review through the lesson and take notes as it tells you in the lesson what each of these are.

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A 10-kg rock falls from a height of 8-m above the ground. What is the kinetic energy of the rock just before it hits the ground?

pishuonlain [190]

Answer: 800

Explanation:

1/2 x m x v^2 = m x g x h

KE = 10 x 10 x 8

KE= 800

3 0

3 years ago

What radiation lies at frequencies just below the frequencies of visible light?

vlabodo [156]

<span>Infrared radiation also called as infrared light was discovered by Sir William Herschel in 1800.It is an electronic magnetic radiation with longer wavelengths than those of a visible light.It involves waves rather than particles. It lies at frequencies just below the frequencies of visible light.</span>

3 0

3 years ago

What is the magnitude of your displacement when you follow directions that tell you to walk 100.0m north, then 25.0m East?

atroni [7]

Answer:

Displacement from the starting position is 103.21m

Explanation:

If you draw these directions, it will create the two legs of a triangle.

Using this method, you can visualize why your displacement is what it is.

Using the pythagorean theorem

${a}^{2} + {b}^{2} = {c}^{2}$

Plug in both values

${100m}^{2} + {25m}^{2} = {c}^{2}$

$c = \sqrt{10652}$

c = 103.2085

c= 103.21

6 0

3 years ago

Are the units of the formula ma = mv2/2 dimensionally consistent? Select the single best answer.

Vesnalui [34]

To solve the problem we will simply perform equivalence between both expressions. We will proceed to place your units and develop your internal operations in case there is any. From there we will compare and look at its consistency

$ma = \text{Mass}\times \text{Acceleration}$

$ma = kg \cdot \frac{m}{s^2}$

At the same time we have that

$\frac{1}{2}mv^2 = \text{Mass}\times \text{Velocity}^2$

$\frac{1}{2}mv^2 = kg ( \frac{m}{s})^2$

$\frac{1}{2}mv^2 = kg \cdot \frac{m^2}{s^2}$

Therefore there is not have same units and both are not consistent and the correct answer is B.

5 0

3 years ago

A cord of mass 0.65 kg is stretched between two supports 28 m apart. if the tension in the cord is 150 n, 2 how long will it tak

MaRussiya [10]

Ans: Time <span>taken by a pulse to travel from one support to the other = 0.348s
</span>
Explanation:
First you need to find out the speed of the wave.

Since
Speed = v = $\sqrt{ \frac{T}{\mu} }$

Where
T = Tension in the cord = 150N
μ = Mass per unit length = mass/Length = 0.65/28 = 0.0232 kg/m

So
v = $\sqrt{ \frac{150}{0.0232} }$ = 80.41 m/s

Now the time-taken by the wave = t = Length/speed = 28/80.41=0.348s

5 0

3 years ago