6/11(5/6)+2/11(5)
=5/11+10/11
=15/11
multiply the number three times by the other number.
This is simply testing if proportions are valid.
Guess-and-check, so the answer would be 40:48, since 5 x 8 = 40 and 6 x 8 = 48, where 8 is the set "constant" number
<u>Answer-</u>
As infinitely many such possible number pairs can be formed, one of the instances of such pair would be (37000 and 307).
<u>Solution-</u>
Suppose the former one is aaaaa and the later one is bbbbb.
The value of 7 in the former is 1000 times greater than in the later, so let's make it 7000 and 7.
Then the numbers will be in the following form,
a7aaa and bbbb7
Again, the value of 3 in the former is 100 times greater than in the later.
Then the numbers will be in the following form,
37aaa and bb3bb7
Substituting all the a's and b's by 0,
we get, 37000 and 307 is a possible set. Replacing 0 with any number from 1-9, will yield another number pair which will satisfy the conditions.
It is a good idea to get familiar with the operation of your calculator. If you're going to use on-line resources to work problems like this, you can make use of any of several good on-line calculators. Google and Bing search boxes will do calculations for you while observing all the rules of the Order of Operations.
The result of this computation is a number that begins 2.56.... Since the hundredths digit is more than 4, the tenths digit is rounded to the next higher value, from 5 to 6.
Rounded to tenths, 2.1√1.488 = 2.6
