Answer:
Option A is correct - While a guitar string is vibrating, you gently touch the midpoint of the string to ensure that the string does not vibrate at that point. The lowest-frequency standing wave that could be present on the string vibrates at twice the fundamental frequency.
Explanation:
Before touching the midpoint of the string, the string vibrates with one loop.
Fundamental frequency, f1 = v/(2*L)
Now, when the midpoint of the guitar string was touched, the string vibrates with two loops.
Hence, f2 = 2*v/(2*L)
f2 = 2*f1
Therefore, compared to the fundamental frequency the frequency would be double.
Option A is correct - While a guitar string is vibrating, you gently touch the midpoint of the string to ensure that the string does not vibrate at that point. The lowest-frequency standing wave that could be present on the string vibrates at twice the fundamental frequency.
F= 6m.m2/r^2
F= (6.673x10^-11)(70)(3.32x10^23)/(2.44x10^6)^2
ANS: F= 260 N=2.60x10^2 N
<span>Thermal energy added means that heat is added to the system to allow the reaction to occur. Processes that undergo this type of reaction are freezing, deposition and sublimation. Thermal energy removed means that heat is released from the system to the surroundings to allow for the reaction to occur. Processes that undergo this type of reaction are condensation, evaporation and melting</span>
If a cell is placed in a hypertonic solution, water will leave the cell, and the cell will shrink. In an isotonic environment, there is no net water movement, so there is no change in the size of the cell. When a cell is placed in a hypotonic environment, water will enter the cell, and the cell will swell.
Scientist judge each others work based mostly on how creative it is.
