When a person is pulled upwards why the motor of the helicopter
Then the potential energy increased of the person is given as
here m = 109 kg
h = 83 m
so here potential energy of the person given as
now power is defined as rate of energy
so it took 55 s to pull the mass so power is given as
now we know that efficiency of motor is given as 69%
so we have
so we have power as
Answer: The horizontal location of the plane will BE OVER THE BOMB
Explanation:
As soon as the bomb was dropped, the bomb will fall under gravity (free fall) and the location of the plane continues to increase horizontally till the bomb reaches the ground which is a falling distance to be travelled by the bomb at 9.8m/s²
Answer:
0.180 m/s
Explanation:
Solving the equations for conservation of momentum and energy for an elastic collision gives ...
v₁' = ((m₁ -m2)v₁ +2m₂v₂)/(m₁ +m₂) . . . . v₁' is the velocity of m₁ after collision
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Here, we have (m₁, m₂, v₁, v₂) = (20 g, 40 g, 0.540 m/s, 0 m/s).
Substituting these values in to the equation for v₁', we have ...
v₁' = ((20 -40)(0.540) +2(40)(0))/(20 +40) = (-20/60)(0.540)
v₁' = -0.180 . . . m/s
The speed of the 20 g block after the collision is 0.180 m/s to the left.