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Naddik [55]
3 years ago
6

Stacy travels 5 times as fast as Eric. Traveling in opposite directions, they are 336 miles apart after 4 hours. Find their rate

s of travel.
Physics
1 answer:
Vilka [71]3 years ago
6 0

Answer:

Eric travelled at 21miles per hour

while stacy travelled at 105miles per hour.

Explanation:

speed = distance/time

then distance = speedxtime.

speed = x

time = 4hrs

Eric's distance after 4hrs = 4x

since stacy is 5 times faster than eric =

stacy's distance = (5x)4 = 20x

Stacy's distance - Eric's distance = 336m

20x - 4x = 336Miles

16x = 336miles

x = 336/16

x = 21miles per hour

so Eric was travelling at 21miles per hour

While Stacy was travelling at 105 miles per hour.

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When the force acting on the body equal to acceleration?
topjm [15]

Answer:

Acceleration and velocity Newton's second law says that when a constant force acts on a massive body, it causes it to accelerate, i.e., to change its velocity, at a constant rate. In the simplest case, a force applied to an object at rest causes it to accelerate in the direction of the force.

5 0
2 years ago
If he leaves the ramp with a speed of 35.0 m/s and has a speed of 33.0 m/s at the top of his trajectory, determine his maximum h
nadezda [96]

Answer:

H = 6.93 m

Explanation:

given data

velocity v = 35 m/s

horizontal component Vx = 33 m/s

solution

we get here maximum height so first we get vertical component here that is express as

Vy = \sqrt{v^2- Vx^2}        .........................1

put here value

Vy = \sqrt{35^2- 33^2}

Vy = 11.66 m/s

and

now we get height

H = \frac{Vy^2}{2g}        .............................2

put here value

H = \frac{11.66^2}{2\times 9.8}

H = 6.93 m

7 0
3 years ago
Do true blackbodies exist in nature?<br><br> Yes or No??
MaRussiya [10]

Answer:

no

Explanation:

4 0
3 years ago
Read 2 more answers
If a current-carrying wire is in a magnetic field, in what direction will a force be exerted on the wire?.
astraxan [27]

Answer:

The magnetic force on a current-carrying wire is perpendicular to both the wire and the magnetic field with direction given by the right hand rule.

4 0
2 years ago
An infant's toy has a 120 g wooden animal hanging from a spring. If pulled down gently, the animal oscillates up and down with a
Morgarella [4.7K]

Answer:

0.37 m

Explanation:

The angular frequency, ω, of a loaded spring is related to the period, T,  by

\omega = \dfrac{2\pi}{T}

The maximum velocity of the oscillation occurs at the equilibrium point and is given by

v = \omega A

A is the amplitude or maximum displacement from the equilibrium.

v = \dfrac{2\pi A}{T}

From the the question, T = 0.58 and A = 25 cm = 0.25 m. Taking π as 3.142,

v = \dfrac{2\times3.142\times0.25\text{ m}}{0.58\text{ s}} = 2.71 \text{ m/s}

To determine the height we reached, we consider the beginning of the vertical motion as the equilibrium point with velocity, v. Since it is against gravity, acceleration of gravity is negative. At maximum height, the final velocity is 0 m/s. We use the equation

v_f^2 = v_i^2+2ah

v_f is the final velocity, v_i is the initial velocity (same as v above), a is acceleration of gravity and h is the height.

h = \dfrac{v_f^2 - v_i^2}{2a}

h = \dfrac{0^2 - 2.71^2}{2\times-9.81} = 0.37 \text{ m}

3 0
3 years ago
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