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MariettaO [177]
3 years ago
15

What is the equivalent resistance of the circuit?

Physics
2 answers:
Sonbull [250]3 years ago
8 0

Answer:

80Ω

Explanation:

Resistance in a series circuit (when one resistor is after another in the same line) is calculated with the following equation

Total resistance = R1 + R2 + R3...Rn

Substitute in your values and solve for total resistance

Total resistance = 60 + 20 = 80Ω

Nikolay [14]3 years ago
3 0

Answer:

80

Explanation:

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Explanation:

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What are some alike things between the ozone layer and the greenhouse effect
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A cylindrical rod of length L is connected across a fixed potential difference, creating a current I through the rod. What would
Inessa05 [86]

Answer:

The value of current through the rod becomes half

i' = \frac{i}{2}

Explanation:

As per Ohm's law we know that the current through a resistor is given as

i = \frac{V}{R}

here we know that

R = \rho \frac{L}{A}

here we know that the length of the cylinder is L and area is A so the value of current through the rod is given as

i = \frac{V A}{\rho L}

now we have change the length of the conductor to twice of initial value and rest all parameters will remain the same

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3 years ago
In one experiment, a student rolls a 2 kg ball such that it collides with a wall with a force of 10,000 N. In a second experimen
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Answer:

(c) The wall exerts a greater force on the 2 kg ball than on the 5 kg ball since the force from the wall on each ball is equal to the force that each ball exerts on the wall.

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According to Newton's third law of motion,"action and reaction are equal and opposite".

If a 2 kg ball exerts a force of 10,000 N on a wall, the wall will also exert a force of 10,000 N on the 2 kg ball but in opposite direction.

Similarly, If a 5 kg ball exerts a force of 5,000 N on a wall, the wall will also exert a force of 5,000 N on the 5 kg ball but in opposite direction.

Regardless of mass of the ball, the wall will exert equal force with which the ball collide with it.

Therefore, the wall exerts a greater force on the 2 kg ball than on the 5 kg ball since the force from the wall on each ball is equal to the force that each ball exerts on the wall.

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