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givi [52]
3 years ago
11

Please help me! I'm stuck and really confused, thank you so much!

Mathematics
1 answer:
Kryger [21]3 years ago
8 0

Answer:

(a) 5 * (2x - 1) = 10x - 5

(b) 6 * x = x + 2x + 3x

(c) \frac{1}{2}(x - 6) = \frac{1}{2}x - 3

(d) y(3x + 4z) = 3xy + 4yz

(e) z(2xy - 3y + 4x) = 2xyz - 3yz + 4xz

Step-by-step explanation:

Solving (a):

Given

10x - 5

Required

Express as a product

Express 10x as 5 * 2x

10x - 5 = 5 * 2x - 5

Apply distributive property

10x - 5 = 5(2x - 1)

10x - 5 = 5 * (2x - 1)

So:

5 * (2x - 1) = 10x - 5

Solving (b):

Given

x + 2x + 3x

Required

Express as a product

Express 2x and 3x as 2 * x and 3 * x, respectively

x + 2x + 3x = x + 2*x + 3*x

Apply distributive property

x + 2x + 3x = x(1 + 2 + 3)

x + 2x + 3x = x(6)

x + 2x + 3x = 6*x

So:

6 * x = x + 2x + 3x

Solving (c):

Given

\frac{1}{2}(x - 6)

Required

Express as a sum/difference

Apply distributive property

\frac{1}{2}(x - 6) = \frac{1}{2}x - \frac{1}{2}*6

\frac{1}{2}(x - 6) = \frac{1}{2}x - \frac{6}{2}

\frac{1}{2}(x - 6) = \frac{1}{2}x - 3

Solving (d):

Given

y(3x + 4z)

Required

Express as a sum/difference

Apply distributive property

y(3x + 4z) = 3x * y + 4z * y

y(3x + 4z) = 3xy + 4yz

Solving (e):

Given

2xyz - 3yz + 4xz

Required

Express as a product

Factorize

2xyz - 3yz + 4xz = 2xy * z - 3y * z + 4x * z

Apply distributive property

2xyz - 3yz + 4xz = z(2xy - 3y + 4x)

So:

z(2xy - 3y + 4x) = 2xyz - 3yz + 4xz

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