The domain is (-infinity, 6] I believe.
Answer:

Step-by-step explanation:


Answer:
(2x - 3) • (x + 4)
Step-by-step explanation:
Step 1 :
Equation at step 1 :
(2x2 + 5x) - 12
Step 2 :
Trying to factor by splitting the middle term
2.1 Factoring 2x2+5x-12
The first term is, 2x2 its coefficient is 2 .
The middle term is, +5x its coefficient is 5 .
The last term, "the constant", is -12
Step-1 : Multiply the coefficient of the first term by the constant 2 • -12 = -24
Step-2 : Find two factors of -24 whose sum equals the coefficient of the middle term, which is 5 .
-24 + 1 = -23
-12 + 2 = -10
-8 + 3 = -5
-6 + 4 = -2
-4 + 6 = 2
-3 + 8 = 5
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -3 and 8
2x2 - 3x + 8x - 12
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (2x-3)
Add up the last 2 terms, pulling out common factors :
4 • (2x-3)
Step-5 : Add up the four terms of step 4 :
(x+4) • (2x-3)
Which is the desired factorization
.72
18/25
Please mark brainliest
Answer:
- Line XY contains ray OX and ray OY
- Line XY contains segment YX
- Ray YX exists in the diagram
Step-by-step explanation:
A ray can be named by any pair of points on an infinite line. Point O, X, and Y on the same line can be used to name rays OX, OY, XY, YX, OY, and XO. The first point named is the end point of the ray. The ray goes through the other point and continues indefinitely.
BA can be the name of a line segment, but not a ray. The line shown does not extend from point B beyond point A.
Any segment can be named by its end points in either order.
So, we have ...
- Line XY contains ray OX and ray OY
- Line XY contains segment YX
- Ray YX exists in the diagram