What is the area of this isosceles triangle.
1 answer:
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Answer:
Step-by-step explanation:
<u><em>The correct question is</em></u>
Which equation represents a parabola that opens upward, has a minimum value of y=3, and has an axis of symmetry at x= 3?
<em>Verify each case</em>
case 1) we have
This a vertical parabola open upward (the leading coefficient is positive)---> is ok
The vertex represent a minimum ---> is ok
The vertex is the point (-3,-6)
The minimum value of y=-6 ----> is not ok
The axis of symmetry is x=-3 ----> is not ok
case 2) we have
This a vertical parabola open upward (the leading coefficient is positive)---> is ok
The vertex represent a minimum ---> is ok
The vertex is the point (-3,3)
The minimum value of y=3 ----> is ok
The axis of symmetry is x=-3 ----> is not ok
case 3) we have
This a vertical parabola open upward (the leading coefficient is positive)---> is ok
The vertex represent a minimum ---> is ok
The vertex is the point (3,-6)
The minimum value of y=-6 ----> is not ok
The axis of symmetry is x=3 ----> is ok
case 4) we have
This a vertical parabola open upward (the leading coefficient is positive)---> is ok
The vertex represent a minimum ---> is ok
The vertex is the point (3,3)
The minimum value of y=3 ----> is ok
The axis of symmetry is x=3 ----> is ok