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3 years ago

What are the outermost electrons of an atom

2 answers:

7 0

The number of electrons in the outermost shell of a particular atom determines its reactivity, or tendency to form chemical bonds with other atoms. This outermost shell is known as the valence shell, and the electrons found in it are called valence electro

musickatia [10]3 years ago

5 0

Answer:Valence Shell

Explanation: The Valence Shell is the outermost orbital of an atom. The Valence Shell electrons are used in making chemical bonds and are the reason the atom has its physical and chemical properties.

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A student mixes in a test tube 3.00mL of 0.050M CuSO4with 7.00mL of 0.20M NH3/NH41 . The solution becomes a deep blue color. Ass

valkas [14]

Answer:

$\large \boxed{\text{0.0035 mol/L}}$

Explanation:

We are given the volumes and concentrations of two reactants, so this is a limiting reactant problem.

We know that we will need moles, so, lets assemble all the data in one place.

Cu²⁺ + 4NH₃ ⟶ Cu(NH₃)₄²⁺

V/mL: 3.00 7.00

c/mol·L⁻¹: 0.050 0.20

1. Identify the limiting reactant

(a) Calculate the moles of each reactant

$\text{Moles of Cu}^{2+}= \text{3.00 mL solution} \times \dfrac{\text{0.050 mmol Cu}^{2+}}{\text{1 mL solution}} = \text{0.150 mmol Cu}^{2+}\\\\\text{Moles of NH}_{3} = \text{7.00 mL solution} \times \dfrac{\text{0.20 mmol NH}_{3}}{\text{1 mL solution}} = \text{0.140 mmol NH}_{3}$

(b) Calculate the moles of Cu(NH₃)₄²⁺ that can be formed from each reactant

(i) From Cu²⁺

$\text{Moles of Cu(NH$_{3}$)$_{4}$$^{2+}$} = \text{0.150 mmol Cu}^{2+} \times \dfrac{\text{1 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$}}{\text{1 mmol Cu}^{2+}}\\\\= \text{0.150 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$}$

(ii) From NH₃

$\text{Moles of Cu(NH$_{3}$)$_{4}$$^{2+}$} = \text{0.140 mmol NH}_{3} \times \dfrac{\text{1 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$}}{\text{4 mmol NH}_{3}}\\\\= \text{0.0350 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$}$

NH₃ is the limiting reactant, because it forms fewer moles of the complex ion.

(c) Concentration of the complex ion

$\text{The reaction forms 0.0350 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$ in a total volume of 10.00 mL.}\\c = \dfrac{\text{moles}}{\text{litres}} = \dfrac{\text{0.0350 mmol}}{\text{10.00 mL}} = \textbf{0.0035 mol/L}\\\\\text{The concentration of the complex ion is $\large \boxed{\textbf{0.0035 mol/L}}$}$

7 0

3 years ago

using volumetric flask, 1.00 g NaOH was dissolved in water to make 500.0 mL solution. calculate the molarity

Aleksandr-060686 [28]

Hey there!:

Molar mass NaOH = 39.997 g/mol

Number of moles ( solute )

n = mass / molar mass

n = 1.00 / 39.997

n = 0.0250 moles of NaOH

Volume in liters:

500.0 mL / 1000 => 0.5 L

Therefore:

Molarity = number of moles / Volume ( L )

Molarity = 0.0250 / 0.5

Molarity = 0.05 M

Hope that helps!

6 0

3 years ago

Consider the partial equation. Br2 + NaF --> Which best completes the chemical equation?

balandron [24]

Answer is (1) - no reaction.

<em>Explanation; </em>

Some of you may think this reaction as a single replacement reaction which gives NaBr + F₂ as products.

But, according to the reactivity of the halogens, reactivity decreases from up to bottom of the group. F is placed above Br. Hence, F is more reactive than Br. Hence, Br can't replace F.

5 0

3 years ago

Read 2 more answers

Which of the following most closely typifies the sintering temperatures in PM? (a) 0.5 Tm, (b) 0.8 Tm, (c) Tm, where Tm = meltin

SashulF [63]

Answer:

The correct option is;

(b) 0.8 Tm

Explanation:

Sintering is a form of heat treatment given to introduce a material in powdery form in order to introduce the properties of integrity and strength

by the application of heat to the powder at a temperature below its melting point.

With regards to imparting favorable metal properties in the metal to undergo sintering such as ductility, toughness, porosity, hardness, strength it is required to select a sintering temperature higher than 0.6 - 0.8 Tm.

3 0

3 years ago

What are the isomers of c3h6br2...

maks197457 [2]

C3H6Br2 2 isomers:- bominated allkane

CH3CH2CHBr2 1,1-dibromopropane
<span>CH3CHBrCH2Br 1,2-dibromopropane

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7 0

4 years ago