I don't know why I am answering this question but assuming C-13 has a natural abundance of 1.07%:
(1.6000x10^4)(0.0107) = 171.2 = 171 atoms of C-13
Answer:
The answer is D.
Explanation:
Volume (V) = l x w x h
V = 4 x 5 x 1.2
V = 20 x 1.2
V = 24
Density = Mass/Volume or D = M/V
D = 85,000/24
D = 3541.66666666
Answer:
pOH = 5.961
Explanation:
To find the pH of a weak base we can use Henderson-Hasselbalch equation for weak bases:
pOH = pKb + log [(CH₃)₃NHCl] / [(CH₃)₃N]
<em>Where pKb is -log Kb = 4.187 and [] could be taken as moles of each specie.</em>
<em />
<em>Moles (CH₃)₃NHCl:</em>
0.0441L * (0.15mol/L) = 6.615x10⁻³moles
<em>Moles (CH₃)₃N:</em>
0.0233L * (0.16mol/L) = 3.728x10⁻³moles
And pOH is:
pOH = pKb + log [(CH₃)₃NHCl] / [(CH₃)₃N]
pOH = 4.187 + log [6.615x10⁻³moles] / [3.728x10⁻³moles]
<h3>pOH = 5.961</h3>
<em />
Ca is the only element perhaps B
