I believe the correct answer from the choices listed above is the first option. When <span>Br2 and NaF are mixed, no reaction would occur since Br cannot replace F in NaF. Hope this answers the question. Have a nice day. Feel free to ask more questions.</span>
Some of you may think this reaction as a single replacement reaction which gives NaBr + F₂ as products.
But, according to the reactivity of the halogens, reactivity decreases from up to bottom of the group. F is placed above Br. Hence, F is more reactive than Br. Hence, Br can't replace F.
