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3 years ago

Consider the partial equation. Br2 + NaF --> Which best completes the chemical equation?

2 answers:

7 0

I believe the correct answer from the choices listed above is the first option. When Br2 and NaF are mixed, no reaction would occur since Br cannot replace F in NaF. Hope this answers the question. Have a nice day. Feel free to ask more questions.

balandron [24]3 years ago

5 0

Answer is (1) - no reaction.

Explanation; 

Some of you may think this reaction as a single replacement reaction which gives NaBr + F₂ as products.

But, according to the reactivity of the halogens, reactivity decreases from up to bottom of the group. F is placed above Br. Hence, F is more reactive than Br. Hence, Br can't replace F.

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Chrissy is doing her chemistry homework and comes across the chemical formula for 3 molecules of nitric acid, represented by 3HN

dybincka [34]

Answer:

Explanation:

The 3 goes to every term in the molecule

3 NHO3

So its

3x1 N's

3x1 H's

3x3 O's

5 0

3 years ago

How is phosphorylation of glyceraldehyde 3-phosphate in the payment phase of glycolysis different from phosphorylation of glucos

svet-max [94.6K]

In the preparatory phase of glycolysis, two molecules of ATP are invested and the hexose chain is cleaved into two triose phosphates. During this, the phosphorylation of glucose and its conversion to glyceraldehyde-3-phosphate take place. During this phase, the conversion of glyceraldehyde-3-phosphate to pyruvate and the coupled formation of ATP take place. Because Glucose is split to yield two molecules of D-Glyceraldehyde-3-phosphate, each step in the payoff phase occurs twice per molecule of glucose.

Glyceraldehyde 3-phosphate dehydrogenase Simultaneous oxidation and phosphorylation of G3P produce 1,3-bisphosphoglycerate (1,3-BPG) and nicotine adenine dinucleotide (NADH).

The divalent cation also affected the response of the enzyme from the endosperm and shoots to adenine nucleotides and inorganic pyrophosphate.

This phase is also called the glucose activation phase. In the preparatory phase of glycolysis, two molecules of ATP are invested and the hexose chain is cleaved into two triose phosphates. During this, the phosphorylation of glucose and its conversion to glyceraldehyde-3-phosphate take place. Steps 1, 2, 3, 4, and 5 together are called the preparatory phase.

For more information on phosphorylation click on the link below:

brainly.com/question/7465103

#SPJ4

7 0

1 year ago

2. What do you get when you add the following

irga5000 [103]

a. one carbon and one oxygen?

Answer:

(1) Carbon + (1) Oxygen = Carbon monoxide (CO)

Explanation:

Carbon monoxide (CO), an odorless, colorless gas, which can cause sudden illness and death, is produced any time a fossil fuel is burned.

https://www.cdc.gov/co/default.htm

b. one carbon and two oxygen?

Answer:

(1) Carbon + (2) Oxygen = Carbon dioxide (CO2)

Explanation:

a colorless, odorless gas produced by burning carbon and organic compounds and by respiration. It is naturally present in air (about 0.03 percent) and is absorbed by plants in photosynthesis.

https://www.britannica.com/science/carbon-dioxide

c. one carbon and four chlorine?

Answer:

(1) Carbon + (4) Chlorine = Carbon tetrachloride (CCl4)

Explanation:

Carbon Tetrachloride is a clear, colorless, volatile and very stable chlorinated hydrocarbon. Carbon Tetrachloride is used as a solvent for oils and fats, as a refrigerant and as a dry-cleaning agent. Inhalation of its vapors can depress central nervous system activity and cause degeneration of the liver and kidneys. Carbon Tetrachloride is reasonably anticipated to be a human carcinogen based on evidence of carcinogenicity in experimental animals.

https://pubchem.ncbi.nlm.nih.gov/compound/carbon_tetrachloride

I hope this helps, if it dose please give brainest, and have a nice day!

8 0

3 years ago

What was the effect of decreasing the copper's mass?

kondor19780726 [428]

Answer:

Increasing the temperature of the copper made the final temperature increase and decreasing the temperature of the copper made the final temperature decrease. ... How does changing the initial mass of the copper affect how much heat energy it has? The more copper, the more heat energy.

Explanation:

3 0

2 years ago

Read 2 more answers

Gas is heated from 480. K to 750. K and the pressure is kept constant, what final volume would result if the original volume was

attashe74 [19]

Charles law gives the relationship between volume and temperature of gas.
It states that at constant pressure volume is directly proportional to temperature
Therefore
V/ T = k
Where V - volume T - temperature in kelvin and k - constant
V1/T1 = V2/T2
Parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
Substituting the values in the equation
267 L/ 480 K = V / 750 K
V = 417 L
Final volume is 417 L

8 0

3 years ago