Answer:
it is not correct I have an answer for ''why''
Explanation:
You need to balance it
s= 2
0=2
S+30•2 --------> SO•3
2 2 2 2
S +3O•2-------->SO•2......MULTIPLY
2 4 2 4......LCM IS 4
2 1 2 1....DIVIDE BY 4
SO NOW WE GOT THE BALANCE NO. WE CAN PUT IT IN THE EQUATIONS.
2S+3O•2 -----> 2SO•3
now you can check the both sides its balances the correct answer is this
Answer:
32.8 C
Explanation:
- Use combined gas law formula and rearrange.
- Hope that helped! Please let me know if you need further explanation.
Answer is: b. more than 7.
The endpoint is the point at which the indicator changes colour in a colourimetric titration and that is point when titration must stop.
For example, basic salt sodium acetate CH₃COONa is formed from the reaction between weak acid (in this example acetic acid CH₃COOH) and strong base (in this example sodium acetate NaOH).
Balanced chemical reaction of acetic acid and sodium hydroxide:
CH₃COOH(aq) + NaOH(aq) → CH₃COONa(aq) + H₂O(l).
Neutralization is is reaction in which an acid (in this example vinegar or acetic acid CH₃COOH) and a base react quantitatively with each other.
The average atomic mass of your mixture is 1.03 u
.
The average atomic mass of H is the weighted average of the atomic masses of its isotopes.
We multiply the atomic mass of each isotope by a number representing its relative importance (i.e., its % abundance).
Thus,
0.99 × 1.01 u = 0.998 u
0.002 × 2.01 u = 0.004 u
0.008 × 3.02 u = <u>0.024 u</u>
TOTAL = 1.03 u
Answer:
3.59x10⁻⁴ mol
Explanation:
Assuming ideal behaviour we can solve this problem by using the<em> PV=nRT formula</em>, where:
- R = 8314.46 Pa·L·mol⁻¹·K⁻¹
We<u> input the data given by the problem</u>:
- 205 Pa * 5.68 L = n * 8314.46 Pa·L·mol⁻¹·K⁻¹ * 390.4 K
And <u>solve for n</u>:
