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8_murik_8 [283]
3 years ago
9

PLEASE HELP ME!!!!!!!!!!!!!

Mathematics
1 answer:
weeeeeb [17]3 years ago
5 0
T=43 and he has because it’s science
You might be interested in
Which expression simplifies to 4 √13<br><br><br> √208<br><br> √17<br><br> √29<br><br> √52
arsen [322]

Answer:

√208

Step-by-step explanation:

Step 1: Convert 4 to √

4² = 16

4 = √16

Step 2: Multiply radicals

√16(√13) = √208

7 0
3 years ago
Read 2 more answers
(5+6p)(2)= IXL simplify the expression
Nadya [2.5K]
10+12p is the answer to that IXL problem
8 0
3 years ago
Need help ASAP!!!!!!
trapecia [35]

Answer:

see explanation

Step-by-step explanation:

x² + 3x + 7 = 5 ( subtract 5 from both sides )

x² + 3x + 2 = 0 ← in standard form

(x + 2)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x ( zero product rule )

x + 2 = 0 → x = - 2

x + 1 = 0 ⇒ x = - 1

--------------------------------------------------------------

x² - 2 = - 2x² + 5x ( subtract - 2x² + 5x from both sides )

3x² - 5x - 2 = 0 ← in standard form

(3x + 1)(x - 2) = 0 ← in factored form

Equate each factor to zero and solve for x

3x + 1 = 0 ⇒ 3x = - 1 ⇒ x = - \frac{1}{3}

x - 2 = 0 ⇒ x = 2

------------------------------------------------------------

(x + 3)² + 4x = 0 ← expand left side using FOIL and simplify

x² + 6x + 9 + 4x = 0

x² + 10x + 9 = 0 ← in standard form

(x + 9)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 9 = 0 ⇒ x = - 9

x + 1 = 0 ⇒ x = - 1

4 0
3 years ago
Dale made a scale drawing of a house and its lot. The scale he used was 1 inch: 7 feet. The actual length of the backyard is 35
Kipish [7]

Answer:

5

Step-by-step explanation:

<em>35/7=5 </em>

8 0
3 years ago
Statistics question; please help.
Alex_Xolod [135]

Answer:

Does this sample provide convincing evidence that the machine is working properly?

Yes.

Step-by-step explanation:

<u>Normal distribution test:</u>

$z=\frac{x- \mu }{ \frac{\sigma}{\sqrt{n}} }=\frac{ (x-\mu)\sqrt{n}}{\sigma}  $

Where,

x: \text{ sample mean}

\sigma: \text{ standard deviation}

n: \text{ sample size determination}

\mu: \text{ hypothesized size of the screw}

$z=\frac{(1.476-1.5)\sqrt{200} }{0.203 } $

$z=\frac{(-0.024)10\sqrt{2} }{0.203 } $

z \approx -1.672

Once the significance level was not given, It is usually taken an assumption of a 5% significance level.

Taking the significance level of 5%, which means a confidence level of 95%, we have a z-value of \pm 1.96

Therefore, we <u>fail to reject the null</u>. It means that the hypothesis test is not statistically significant: the average length is not different from 1.5!

7 0
3 years ago
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