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aleksklad [387]
3 years ago
11

The number of molecules in 48.0 grams of oxygen gas o2 is

Physics
2 answers:
Nataly [62]3 years ago
7 0

Answer:

Ok.

Know this.

1 moles of a gas contains 6.022x10²³molecules.

Given: 48g of Oxygen gas.

Find the moles present

Mole = Mass/Molar Mass

Molar Mass of O2 = 16x2 =32g/mol

Mole = 48/32

=1.5moles of O2.

Recall

1 moles of gas contains 6.022x10²³molecules

1.5moles would contain

1.5 x 6.022x10²³molecules

=9.033 x 10²³ molecules of Oxygen gas.

Have a great day!

jolli1 [7]3 years ago
5 0

Answer:

9.03 times 10times 23 calculate it and there ya go

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       Natural length of a spring is 0.5\text{ }m. The spring is streched by 0.02\text{ }m. The resultant energy of the spring is 0.5\text{ }J.

       The potential energy of an ideal spring with spring constant k and elongation x is given by \dfrac{1}{2}kx^{2}.

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       \text{Potential Energy in the spring = }\dfrac{1}{2}kx^{2}\\0.5\text{ }J\text{ }=\text{ }\dfrac{1}{2}k(0.02\text{ }m)^{2}\\k\times0.0004\text{ }m^{2}\text{ }=\text{ }1\text{ }J\text{ }=\text{ }1\text{ }kg\frac{m^{2}}{s^{2}}\\k\text{ }=\text{ }\dfrac{1\text{ }kg\dfrac{m^{2}}{s^{2}}}{0.0004\text{ }m^{2}}\text{ }=\text{ }2500\text{ }\frac{kg}{s^{2}}

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