Work done = force × displacement
it's given that,
work done is 1500J
and the force applied is 500N
use the above relation to find the displacement,
1500 = 500 × displacement
1500/500 = displacement
3 = displacement
so,
the wheelbarrow move 3m.
Answer:
Explanation:
1) emf stands for elactro-motive force and represents the ability to move electrical charge carriers. Commonly referred to as Volts.
2) P = VI = 1.5(0.31) = 0.465 ≈ <u>0.47 W</u>
3) P = 0.465 - I²R = 0.465 - 0.31²(0.65) = 0.402535 W = J/s ≈ <u>0.40 J</u>
4) 14000 J / 0.40 J/s = <u>35 000 s </u> or about 9.75 hrs
Conservation of momentum so the total initial momentum in the system is equal to the total final momentum in the system. You must remember that if an object is travelling in the negative direction, you must put a negative sign for the velocity.
mv + mv = mv
plug in all the numbers
(0.0323)(4.50) + (0.078)(-1.12) = (0.0323 + 0.078)Vf
multiply everything together
0.14535 - 0.08736 = 0.1103Vf
simplify
0.05799 = 0.1103Vf
isolate for vf
Vf = 0.5257m/s east
Answer:
D(11) = 37.660 m
dD/dt = 2.7260 m/s
Explanation:
given data
two path apart = 17 m
walks east one path = 4 km/h = 1.111 m/s
walks west other path = 7 km/h = 1.944 m/s
pass each other time t = 0
solution
we consider here east is the positive direction and west is the negative direction
so that
the east - west distance between them is = 1.111 + 1.944 = 3.055 m/s
and
the actual distance between them time t is
D(t) =
at time 11 s
D(11) =
D(11) = 37.660 m
and
increase rate is dD/dt
dD/dt =
so for 11 sec
dD/dt =
dD/dt = 2.7260 m/s
When a satellite is revolving into the orbit around a planet then we can say
net centripetal force on the satellite is due to gravitational attraction force of the planet, so we will have
now we can say that kinetic energy of satellite is given as
also we know that since satellite is in gravitational field of the planet so here it must have some gravitational potential energy in it
so we will have
so we can say that energy from the fuel is converted into kinetic energy and gravitational potential energy of the satellite