Answer:
Explanation:
11 = y/3+7
collecting like terms
11 - 7 = y/3
4 = y/3
multiplying both sides by 3 gives us
12 = y
therefore
y = 12
But the fact is that an accelerating object is an object that is changing it’s velocity.. for this reason , it can be safely concluded that an object moving in a circle at constant speed is indeed accelerating. It is accelerating because the direction of the velocity vector is changing .
Answer:
Explanation:
We shall represent speed in vector form
First speed
v₁ = 1.5 cos 14 i + 1.5 sin 14 j
= 1.455 i + 0.363 j
v₂ = 4.4 cos 33 i + 4.4 sin 33 j
= 3.69 i + 2.39 j
v₂ - v₁
3.69 i + 2.39 j - 1.455 i - 0.363 j
= 2.235 i + 2.027 j
acceleration
= v₂ - v₁ / time
= ( 2.235 i + 2.027 j ) / 23
= .097 i + .088 j
force = mass x acceleration
= 398 x ( .097 i + .088 j )
= 38.6 i + 35.02 j
Magnitude of force F
F² = 38.6² + 35.02²
F = 52.11 N
Tan θ = 35.02 / 38.6
θ = 42° north of east.
Answer:
811.54 W
Explanation:
Solution
Begin with the equation of the time-averaged power of a sinusoidal wave on a string:
P = 
μ.T².ω².v
The amplitude is given, so we need to calculate the linear mass density of the rope, the angular frequency of the wave on the rope, and the frequency of the wave on the string.
We need to calculate the linear density to find the wave speed:
μ = 
= 0.123Kg/3.54m
The wave speed can be found using the linear mass density and the tension of the string:
v= 22.0 ms⁻¹
v = f/λ = 22.0/6.0×10⁻⁴
= 36666.67 s⁻¹
The angular frequency can be found from the frequency:
ω= 2πf=2π(36666.67s−1) = 2.30 ×10⁻⁵s⁻¹
Calculate the time-averaged power:
P =
μΤ²×ω²×ν
= ×( 0.03475kg/m)×(0.0002)²×(2.30×10⁵)² × 22.0
= 811.54 W
