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2 years ago

Energy travels at right angles to the direction of the vibrating particles in ________ waves.

Physics

1 answer:

marshall27 [118]2 years ago

5 0

Energy travels at right angles to the direction of the vibrating particles in Transverse waves

<h3>What is a transverse wave oceanography?</h3>

Energy can flow from one spot to another in a wave phenomenon, but the particles of matter in the medium return to their fixed position. A wave transmits energy without moving mass. Although waves can be observed moving through an ocean or lake, the water always returns to its resting place. The medium's particles just vibrate in situ. As they vibrate, the energy of the disturbance is passed on to the particles next to them, who then pass it on to the particles next to them, and so on.

Transverse waves can only go through solids, but longitudinal waves can travel through solids, liquids, and gases.

Transverse waves cause the medium to travel perpendicular to the wave's direction.

Learn more about Transverse waves refer:

brainly.com/question/13863548

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A circuit has a known resistance of 5 Ohms. An ammeter in the circuit gives a reading of 5 Amps. What is the Voltage of the circ

artcher [175]

E = I R

Voltage = (current)×(resistance).

V = 5A x 5 ohms = 25 volts.

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3 years ago

A frequently quoted rule of thumb in aircraft design is that wings should produce about 1000 N of lift per square meter of wing.

svetlana [45]

Answer:

v₂ = 63.62 m / s

Explanation:

For this exercise in fluid mechanics we will use Bernoulli's equation

P₁ + ρ g v₁² + ρ g y₁ = P₂ + ρ g v₂² + ρ g y₂

where the subscript 1 refers to the inside of the wing and the subscript 2 to the top of the wing.

We will assume that the distance between the two parts is small, so y₁ = y₂

P₁-P₂ = ρ g (v₂² - v₁²)

pressure is defined by

P = F / A

we substitute

ΔF / A = ρ g (v₂² - v₁²)

v₂² = $\frac{\Delta F}{A \ \rho \ g} + v_1^2$

suppose that the area of the wing is A = 1 m²

we substitute

v₂² = $\frac{1000}{1 \ 1.29 \ 9.8} + 63^2$

v₂² = 79.10 + 3969

v₂ = √4048.1

v₂ = 63.62 m / s

7 0

3 years ago

You pull a 70-kg crate at an angle of 30° above the horizontal. If you pull with a force of 600N and the coefficient of kinetic

Alenkinab [10]

Answer:

Explanation:

Force of friction acting on the body = μ mg cosθ

= .4 x 70 x 9.8 x cos30

= 237.63 N

component of weight = mgsinθ

= 70 x 9.8 x sin30

= 343 N

Net upward force = 600 - mgsinθ - μ mg cosθ

= 600 - 343 - 237.63

= 105.37 N

acceleration in upward direction = 105.37 / 70

= 1.5 m /s²

s = ut + 1/2 a t²

= 0 + .5 x 1.5 x 3²

= 6.75 m .

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3 years ago

As a laudably skeptical physics student, you want to test Coulomb's law. For this purpose, you set up a measurement in which a p

Oksana_A [137]

Answer:

a.Attractive

$2.31531\times 10^{-16}\ N$

Explanation:

When it comes to charges, the charges which are alike repel each other and the charges which are different will attract each other.

Here, there is a proton and electron which are different particles hence, they will attract each other.

$q_1=q_2$ = Charge of electron and proton = $1.6\times 10^{-19}\ C$

r = Distance between them = 997 nm

k = Coulomb constant = $8.99\times 10^{9}\ Nm^2/C^2$

Force is given by

$F=\dfrac{kq_1q_2}{r^2}\\\Rightarrow F=\dfrac{8.99\times 10^9\times 1.6\times 10^{-19}\times 1.6\times 10^{-19}}{(997\times 10^{-9})^2}\\\Rightarrow F=2.31531\times 10^{-16}\ N$

The force of attraction between the particles will be $2.31531\times 10^{-16}\ N$

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3 years ago

I pooped in the bathtub? I tryed to poop in my hand so i can carry it to the fish tank so they can feed thereselfs but it fell t

cupoosta [38]

Answer:

Sorry don't know

Explanation:

Ask google

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2 years ago