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alexandr1967 [171]
2 years ago
11

Energy travels at right angles to the direction of the vibrating particles in ________ waves.

Physics
1 answer:
marshall27 [118]2 years ago
5 0

Energy travels at right angles to the direction of the vibrating particles in Transverse waves

<h3>What is a transverse wave oceanography?</h3>

Energy can flow from one spot to another in a wave phenomenon, but the particles of matter in the medium return to their fixed position. A wave transmits energy without moving mass. Although waves can be observed moving through an ocean or lake, the water always returns to its resting place. The medium's particles just vibrate in situ. As they vibrate, the energy of the disturbance is passed on to the particles next to them, who then pass it on to the particles next to them, and so on.

Transverse waves can only go through solids, but longitudinal waves can travel through solids, liquids, and gases.

Transverse waves cause the medium to travel perpendicular to the wave's direction.

Learn more about Transverse waves   refer:

brainly.com/question/13863548

#SPJ4

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g You drop a 3.6-kg ball from a height of 3.5 m above one end of a uniform bar that pivots at its center. The bar has mass 9.9 k
Salsk061 [2.6K]

Answer:

h = 3.5 m

Explanation:

First, we will calculate the final speed of the ball when it collides with a seesaw. Using the third equation of motion:

2gh = v_f^2 - v_i^2\\

where,

g = acceleration due to gravity = 9.81 m/s²

h = height = 3.5 m

vf = final speed = ?

vi = initial speed = 0 m/s

Therefore,

(2)(9.81\ m/s^2)(3.5\ m) = v_f^2 - (0\ m/s)^2\\v_f = \sqrt{68.67\ m^2/s^2}\\v_f = 8.3\ m/s

Now, we will apply the law of conservation of momentum:

m_1v_1 = m_2v_2

where,

m₁ = mass of colliding ball = 3.6 kg

m₂ = mass of ball on the other end = 3.6 kg

v₁ = vf = final velocity of ball while collision = 8.3 m/s

v₂ = vi = initial velocity of other end ball = ?

Therefore,

(3.6\ kg)(8.3\ m/s)=(3.6\ kg)(v_i)\\v_i = 8.3\ m/s

Now, we again use the third equation of motion for the upward motion of the ball:

2gh = v_f^2 - v_i^2\\

where,

g = acceleration due to gravity = -9.81 m/s² (negative for upward motion)

h = height = ?

vf = final speed = 0 m/s

vi = initial speed = 8.3 m/s

Therefore,

(2)(9.81\ m/s^2)h = (0\ m/s)^2-(8.3\ m/s)^2\\

<u>h = 3.5 m</u>

6 0
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Ganezh [65]

Answer:

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Explanation:

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ki77a [65]

Answer:

point b

Explanation:

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3 years ago
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kolbaska11 [484]
To answer the problem we would be using this formula which isE = hc/L where E is the energy, h is Planck's constant, c is the speed of light and L is the wavelength 
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