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2 years ago

Energy travels at right angles to the direction of the vibrating particles in ________ waves.

Physics

1 answer:

marshall27 [118]2 years ago

5 0

Energy travels at right angles to the direction of the vibrating particles in Transverse waves

<h3>What is a transverse wave oceanography?</h3>

Energy can flow from one spot to another in a wave phenomenon, but the particles of matter in the medium return to their fixed position. A wave transmits energy without moving mass. Although waves can be observed moving through an ocean or lake, the water always returns to its resting place. The medium's particles just vibrate in situ. As they vibrate, the energy of the disturbance is passed on to the particles next to them, who then pass it on to the particles next to them, and so on.

Transverse waves can only go through solids, but longitudinal waves can travel through solids, liquids, and gases.

Transverse waves cause the medium to travel perpendicular to the wave's direction.

Learn more about Transverse waves refer:

brainly.com/question/13863548

#SPJ4

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What is the density of a 2 gallon milk jug that has a mass of 2.0 kg? Answer should be in g/ml.

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volume of milk is given as

$V = 2 Gallon$

we will convert it into mL unit

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4 years ago

A 36.0 kg box initially at rest is pushed 5.00 m along a rough, horizontal floor with a constant applied horizontal force of 130

konstantin123 [22]

Answer:

(a) W = 650J

(b) Wf = 529.2J

(d) W = 0J

(e) ΔK = 120.8J

(f) v2 = 2.58 m/s

Explanation:

(a) In order to find the work done by the applied force you use the following formula:

$W=Fd$ (1)

F: applied force = 130N

d: distance = 5.0m

$W=(130N)(5.0m)=650J$

The work done by the applied force is 650J

(b) The increase in the internal energy of the box-floor system is given by the work done of the friction force, which is calculated as follow:

$W_f=F_fd=\mu Mgd$ (2)

μ: coefficient of friction = 0.300

M: mass of the box = 36.0kg

g: gravitational constant = 9.8 m/s^2

$W_f=(0.300)(36.0kg)(9.8m/s^2)(5.0m)=529.2J$

The increase in the internal energy is 529.2J

(c) The normal force does not make work on the box because the normal force is perpendicular to the motion of the box.

$W = 0J$

(d) The same for the work done by the normal force. The work done by the gravitational force is zero because the motion of the box is perpendicular o the direction of the gravitational force.

(e) The change in the kinetic energy is given by the net work on the box. You use the following formula:

$\Delta K=W_T$ (3)