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miskamm [114]
3 years ago
10

Four football players are running down the field at the same speed. Player 1 weighs 180 lbs and is running toward the south goal

, player 2 weighs 200 lbs and is running toward the north goal, player 3 weighs 190 lbs and is running toward the north goal, and player 4 weighs 165 lbs and is running toward the south goal. Which player has the most momentum?
Physics
2 answers:
Ivanshal [37]3 years ago
4 0

Its player 2 because they are all traveling at the same speed yet player 2 has the most mass

ANTONII [103]3 years ago
3 0
Player 4 ..................
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A ball having mass 2 kg is connected by a string of length 2 m to a pivot point and held in place in a vertical position. A cons
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Complete Question

A ball having mass 2 kg is connected by a string of length 2 m to a pivot point and held in place in a vertical position. A constant wind force of magnitude 13.2 N blows from left to right. Pivot Pivot F F (a) (b) H m m L L If the mass is released from the vertical position, what maximum height above its initial position will it attain? Assume that the string does not break in the process. The acceleration of gravity is 9.8 m/s 2 . Answer in units of m.What will be the equilibrium height of the mass?

Answer:

H_m=1.65m

H_E=1.16307m

Explanation:

From the question we are told that

Mass of ball M=2kg

Length of string L= 2m

Wind force F=13.2N

Generally the equation for \angle \theta is mathematically given as

tan\theta=\frac{F}{mg}

\theta=tan^-^1\frac{F}{mg}

\theta=tan^-^1\frac{13.2}{2*2}

\theta=73.14\textdegree

Max angle =2*\theta= 2*73.14=>146.28\textdegree

Generally the equation for max Height H_m is mathematically given as

H_m=L(1-cos146.28)

H_m=0.9(1+0.8318)

H_m=1.65m

Generally the equation for Equilibrium Height H_E is mathematically given as

H_E=L(1-cos73.14)

H_E=0.9(1+0.2923)

H_E=1.16307m

8 0
2 years ago
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