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Katyanochek1 [597]
3 years ago
9

Where do most typical exhaust leaks occur?

Physics
1 answer:
pentagon [3]3 years ago
3 0

Answer:

an exhaust leak is most likely in your systems manifold or any of the joints along the exhaust system if the leak is the manifold not only will your engine volume increase. but some of them can be located and a running vehicle in the engine bay

Explanation:

lol hope it helps^^ I'm no expert but I'm just giving info

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Help ASAP! I'm taking a test! thank you all xoxo
Stels [109]

Answer:

<h2><em><u>atoms can form new substances </u></em></h2>
5 0
3 years ago
A sample of a monatomic ideal gas initially at temperature T, undergoes a process during which the pressure of the gas triples a
Allisa [31]

Answer:

B) 8 T.

Explanation:

For an ideal gas , the gas law that it follow is as follows

P₁V₁ / T₁ = P₂ V₂ /T₂

This law is followed by all the gases whether mono atomic or diatomic.

In this case following information are given

P₂ / P₁ = 3

V₂ / V₁ = 3

T₁ = T

T₂ = ?

From the gas law formula given , we have

T_2 =\frac{P_2\times V_2\times T_1}{P_1\times V_1}

V_2 = \frac{P_2}{P_1} \times\frac{V_2}{V_1}\times T

= 3 X 3 T

= 9 T

Change in temperature = 9T - T = 8 T.

7 0
3 years ago
Which of the following statements is not true?
djyliett [7]

Answer:

Explanation:

1 ) Average power supplied to an inductor is zero because the phase difference of potential and current is π / 2 .

So it is a wrong statement .

2 ) Step up transformer increases the voltage . At high voltage , lesser current is required to transport electrical energy . When current is reduced , the loss of energy due to heating effect is reduced .

3 ) voltage and current are in phase in resistance  in ac .

3 ) RMS stands for Root Mean Square .

4 0
4 years ago
An object travels a given distance at a speed of 5 m/s. If the object travels the same distance at a higher speed, how will the
OverLord2011 [107]

a. it will take less time

4 0
4 years ago
Read 2 more answers
A simple Atwood’s machine uses a massless
Lady bird [3.3K]
The Atwood's machine is in motion starting from rest, then Vf = Vo + a(t). 
<span>Final Velocity is given as 6.7 m/s and the time is 1.9 s thus 6.7= 0+ a(1.9) </span>
<span>then a = 6.7/1.9 = 3.526 m/s². </span>
<span>The Atwood's Machine also has the formula d= distance = 1/2a(t²) </span>
<span>distance given is 6.365 m , then 6.365 = 1/2 a (1.9)², </span>
<span>a = 3.526 m/s² the same acceleration. </span>
<span>a= g(m1-m2) / m1+m2) </span>
<span>m1a + m2a = m1g - m2g </span>
<span>m1a - m1g = -m2g - m2a </span>
<span>3.526 m1 - 9.81 m1 = -9.81m2 - 3.526 m2 </span>
<span>-6.28 m1 = -13.34 m2 </span>
<span>0.47 m1= m2 </span>
<span>if 24J = 1/2mv² </span>
<span>then 24J = 1/2 m1 ( 6.7)² </span>
<span>48/ 44.89 = m1 </span>
<span>1.069 kg = m1 , then </span>
<span>0.47(1.069) = m2 </span>
<span>0.503 kg = m2</span>
6 0
4 years ago
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