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rosijanka [135]
3 years ago
7

I push a box with mass 10 kg across a 15 m room. If I apply a force of 20N to do this how much work is being done on the box?

Physics
1 answer:
devlian [24]3 years ago
8 0
You could use the formula

W=Fd

F(force)=20N

D(distance/displacement) =15m

W=(20N)(15m)

W= 300 J
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Bolt starts the race not moving, but then increased his speed until he reaches a top speed. Once Bolt reaches his top speed he m
LekaFEV [45]

Answer:

a

Explanation:

<u>In order to maintain speed, a moving object or person must move at a constant velocity</u>. Accelerating will increase the speed while decelerating will reduce the speed.

Hence, for Bolt to be able to maintain the top speed for a few seconds, he needs to move at a constant velocity.

The correct option is a.

7 0
2 years ago
A system proposed by the U.S. Navy for underwater submarine communication, called ELF (for extremely low frequency), operates wi
kow [346]

Answer

Wavelength= 30*20^8/30=10^7m

Explanation:

Velocity = frequency *wavelength

We're frequency=30HZ

Velocity of light= 3*10^8m/s

Wavelength= 30*20^8/30=10^7m

Explanation:

7 0
3 years ago
Read 2 more answers
Calculate the final velocity right after a 117 kg rugby player who is initially running at 7.45 m/s collides head‑on with a padd
Free_Kalibri [48]

Answer:

v_f = 0.87 m/s

Explanation:

We are given;

F_avg = -17700 N (negative because it's backward)

m = 117 kg

Δt = 5.50 × 10^(−2) s

v_i = 7.45 m/s

Now, formula for impulse is given by;

I = F•Δt = - 17700 x 5.50 × 10^(−2) = - 973.5 kg.m/s

From impulse momentum theory, we know that;

Change in momentum of particle is equal to impulse.

Thus,

Δp = I = m•v_f - m•v_i

Thus,

-973.5= 117(v_f - 7.45)

Thus,

-973.5/117 = (v_f - 7.45)

-8.3205 + 7.45 = v_f

v_f = - 0.87 m/s

We'll take absolute value as;

v_f = 0.87 m/s

5 0
3 years ago
Maria and Ben are both suffering from a hereditary disease, as described in the following table.
Margaret [11]
The answer is option B
3 0
3 years ago
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The focal length of the lens of a simple digital camera is 40 mm, and it is originally focused on a person 25 m away. In what di
ss7ja [257]

Answer:

Explanation:

Here image distance is fixed .

In the first case if v be image distance

1 / v - 1 / -25 = 1 / .05

1 / v = 1 / .05 - 1 / 25

= 20 - .04 = 19.96

v = .0501 m = 5.01 cm

In the second case

u = 4 ,

1 / v - 1 / - 4 = 1 / .05

1 / v = 20 - 1 / 4 = 19.75

v = .0506 = 5.06 cm

So lens must be moved forward by 5.06 - 5.01 =  .05 cm ( away from film )

3 0
3 years ago
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