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rosijanka [135]
3 years ago
7

I push a box with mass 10 kg across a 15 m room. If I apply a force of 20N to do this how much work is being done on the box?

Physics
1 answer:
devlian [24]3 years ago
8 0
You could use the formula

W=Fd

F(force)=20N

D(distance/displacement) =15m

W=(20N)(15m)

W= 300 J
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When an object of mass m1 is hung on a vertical spring and set into vertical simple harmonic motion, its frequency is 12Hz. When
anzhelika [568]

Answer:

Explanation:

Given

When m_1 mass is attached to the spring its frequency is f_1=12\ Hz

when another mass m_2 is attached to m_1 , frequency changes to f_2=4\ Hz

frequency of spring mass system is given by

f=\frac{1}{2\pi }\sqrt{\frac{k}{m}}

for m_1

f_1=\frac{1}{2\pi }\sqrt{\frac{k}{m_1}}

12=\frac{1}{2\pi }\sqrt{\frac{k}{m_1}}-----1

for m_1 and m_2

f_2=\frac{1}{2\pi }\sqrt{\frac{k}{m_1+m_2}}

4=\frac{1}{2\pi }\sqrt{\frac{k}{m_1+m_2}}----2

divide 1 and 2

3=\sqrt{\frac{m_1+m_2}{m_1}}

squaring

9=1+\frac{m_2}{m_1}

\frac{m_2}{m_1}=8

   

8 0
3 years ago
An x-ray has a wavelength of 4.18 Å. Calculate the energy (in J) of one photon of this radiation. Enter your answer in scientifi
Damm [24]

Answer:

E = 4.75 x 10⁻¹⁶ J

Explanation:

given,

wavelength of the x-ray , λ = 4.18 Å

Energy of photon = ?

we know

E = \dfrac{hc}{\lambda}

where h is the planks constant

          c is the speed of light

h = 6.626 x 10⁻³⁴ m² kg / s

c = 3 x 10⁸ m/s

now,

E = \dfrac{6.626\times 10^{-34}\times 3 \times 10^8}{4.18\times 10^{-10}}

E = 4.75 x 10⁻¹⁶ J

hence, the energy of the photon is equal to E = 4.75 x 10⁻¹⁶ J

4 0
4 years ago
In a women's 100-m race, accelerating uniformly, laura takes 1.96 s and healan 3.11 s to attain their maximum speeds, which they
liubo4ka [24]
First we write the kinematic equations
 a
 v = a * t + vo
 r = (1/2) at ^ 2 + vo * t + ro
 We have then that:
 (10.4 - t) = time that they run at their maximum speed
 For Laura:
 d = (1/2) at ^ 2 + (at) (10.4 - t)
 100 m = (1/2) a (1.96) ^ 2 + [(1.96) a] (8.44)
 100 = 1.9208a + 16.5424a
 100 = 18.4632a
 a = 100 / 18.4632 = 5.42 m / s ^ 2
 For Healen:
 100 = (1/2) a (3.11) ^ 2 + [(3.11) a] (7.29)
 100 = 4.83605a + 22.6719a
 100 = 27.50795a
 a = 100 / 27.50795
 a = 3.64 m / s ^ 2
 Answer:
 the acceleration of each sprinter is
 Laura: 5.42 m / s ^ 2
 Healen 3.64 m / s ^ 2
3 0
3 years ago
4. A truck with a mass of 6,500 Kg can exert a force of 29,250 N when stopping. What is the deceleration
Vitek1552 [10]
Deceleration = 29250 / 6500 = 4.5 m/s^2
7 0
4 years ago
Plz and ty ... free points, be nice
harkovskaia [24]

Answer:

Thank you!

Explanation:

5 0
3 years ago
Read 2 more answers
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