Question

During an extremely foggy day during the medieval era, an architect wants to determine the height of a building. He cannot see to the top of his building, but he stands on the roof and lowers a pendulum to the ground. If the pendulum swings with a period of 12 seconds, what is the height of the building?

Answer 1

Answer:

Height of the building = 35.78 m

Explanation:

Given that,

The time period of a pendulum is, T = 12 s

We need to find the height of the building. The formula for the time period of a pendulum is given by :

$T=2\pi \sqrt{\dfrac{l}{g}}$

Where

l is the height of the building

$l=\dfrac{T^2g}{4\pi^2}\\\\l=\dfrac{(12)^2\times 9.8}{4\times 3.14^2}\\\\l=35.78\ m$

So, the height of the building is 35.78 m.