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NeX [460]
2 years ago
5

Which phrases describe the open-ocean zone? Check all that apply.

Chemistry
2 answers:
ASHA 777 [7]2 years ago
3 0

Answer:

- few nutrients

- low temperatures

-very little sunlight

Explanation:

miss Akunina [59]2 years ago
3 0

Answer:

I think it's: located near coasts.

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How do electrons transition between energy levels?
kow [346]
The electron with its extra packet of energy becomes excited, and promptly moves out of its lower energy level and takes up a position in a higher energy level.
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3 years ago
Molecule of dissimilar elements with a net charge remaining is called
MariettaO [177]
It is called a polyatomic ion. 

 Hope this helps!!!
3 0
3 years ago
O tetraclorometano é um solvente muito utilizado na indústria de transformaç?o de produtos orgânicos ele é produzido pela reaç?o
Vlada [557]

Answer:

ΔHr = -103,4 kcal/mol

Explanation:

<u>Using:</u>

<u>AH° (kcal/mol) </u>

<u>Metano (CH) </u>

<u>-17,9 </u>

<u>Cloro (CI) </u>

<u>tetraclorometano (CCI) </u>

<u>- 33,3 </u>

<u>Acido cloridrico (HCI) </u>

<u>-22</u>

It is possible to obtain the ΔH of a reaction from ΔH's of formation for each compound, thus:

ΔHr = (ΔH products - ΔH reactants)

For the reaction:

CH₄(g) + Cl₂(g) → CCl₄(g) + HCl(g)

The balanced reaction is:

CH₄(g) + 4Cl₂(g) → CCl₄(g) + 4HCl(g)

The ΔH's of formation for these compounds are:

ΔH CH₄(g): -17,9 kcal/mol

ΔH Cl₂(g): 0 kcal/mol

ΔH CCl₄(g): -33,3 kcal/mol

ΔH HCl(g): -22 kcal/mol

The ΔHr is:

-33,3 kcal/mol × 1 mol + -22 kcal/mol× 4 mol - (-17,9 kcal/mol × 1 mol + 0kcal/mol × 4mol)

<em>ΔHr = -103,4 kcal/mol</em>

<em></em>

I hope it helps!

3 0
3 years ago
The density of gold is 19.32 g/mL. What is the volume, in mL, of a nugget of gold with a mass of 55.07 g?
Vika [28.1K]

Answer: 2.850

Explanation:

19.32=\frac{55.07}{v}\\19.32v=55.07\\v=\frac{55.07}{19.32}=\boxed{2.850 \text{ mL}}

5 0
2 years ago
How much pv work is done in kilojoules for the reaction of 0.68 mol of h2 with 0.34 mol of o2 at atmospheric pressure if the vol
dsp73
The delta H of -484 kJ is the heat given off when 2 moles of H2 react with 1 mole of O2 to make 2 moles of H2O. You don't have anywhere near that much reactants, only 1/4 as much

<span>actual delta H = 0.34  moles H2 x (-484 kJ / 2 moles H2) = 823 kJ </span>

<span>delta E = delta H - PdeltaV = 823 kJ - 0.41 kJ = 822 kJ</span>
3 0
3 years ago
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