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omeli [17]
2 years ago
13

Which of the following is

Chemistry
2 answers:
zimovet [89]2 years ago
8 0

Answer:

<h3>D</h3><h3>kidneys </h3>

Explanation:

I hope it helps

Fed [463]2 years ago
6 0

Answer:

Kidneys

Explanation:

I learned about it :)

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A solution is 12.5% Na3PO, by mass. How many grams of Na3PO4
Harman [31]
<h2>Answer:  4.94 g   </h2>

Explanation:

Mass of solution of Na₃PO₄ = volume  × density

                                              =   35.9 mL × 1.10 g/mL

                                              =   39.49 g

Now, since the solution only contains 12.5% Na₃PO₄, then the mass of Na₃PO₄ is 12.5% of 39.49 g

                                 12.5% × 39.49 g = <u>4.94 g   </u>        

7 0
2 years ago
What’s the equation to solid calcium oxide reacts with hydrochloric acid to form a solution of calcium chloride and water as it’
meriva

Answer: CaO + 2HCl —> CaCl2 + H2O

Explanation:

3 0
3 years ago
2CH2(g) + 50 (g) → 400/(g) + 2 H2O(g)
Nadusha1986 [10]

168.96 g of carbon dioxide (CO₂)

Explanation:

The chemical reaction representing the combustion of acetylene:

2 C₂H₂ (g) + 5 O₂ (g)→ 4 CO₂ (g) + 2 H₂O (g)

number of moles = mass / molecular weight

number of moles of acetylene (C₂H₂) = 50 / 26 = 1.92 moles

Taking in account the stoichiometry of the chemical reaction, we devise the following reasoning:

if       2 moles of acetylene (C₂H₂) produces 4 moles of carbon dioxide (CO₂)

then 1.92 moles of acetylene (C₂H₂) produces X moles of carbon dioxide (CO₂)

X = (1.92 × 4) / 2 = 3.84 moles of carbon dioxide (CO₂)

mass = number of moles × molecular weight

mass of carbon dioxide (CO₂) = 3.84 × 44 = 168.96 g

Learn more about:

combustion of hydrocarbons

brainly.com/question/4919676

brainly.com/question/1406903

#learnwithBrainly

6 0
3 years ago
A container is filled with helium gas. It has a volume of 2.25 liters and contains 9.00 moles of helium. How many moles of heliu
Darina [25.2K]

Answer: There are 7.4 moles of helium gas present in a 1.85 liter container at the same temperature and pressure.

Explanation:

Given: V_{1} = 2.25 L,     n_{1} = 9.0 mol

V_{2} = 1.85 L,            n_{2} = ?

Formula used to calculate the moles of helium are as follows.

\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\

Substitute the values into above formula as follows.

\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\\frac{2.25 L}{9.0 mol} = \frac{1.85 L}{n_{2}}\\n_{2} = \frac{1.85 L \times 9.0 mol}{2.25 L}\\= 7.4 mol

Thus, we can conclude that there are 7.4 moles of helium gas present in a 1.85 liter container at the same temperature and pressure.

7 0
2 years ago
compound 1 contains 15.0g of hydrogen and 120.0g oxygen. What is the percent compound of each element?
allsm [11]

Note down the formula below

\boxed{\sf Mass\%\;of\; element=\dfrac{Mass\:of\:the\: element}{Mass\;of\:the\: compound}\times 100}

Mass of the compound

\\ \sf\longmapsto 15+120=135g

Mass % of Hydrogen:-

\\ \sf\longmapsto \dfrac{15}{135}\times 100

\\ \sf\longmapsto \dfrac{1}{9}\times 100

\\ \sf\longmapsto 11.1\%

Mass % of Oxygen:-

\\ \sf\longmapsto \dfrac{120}{135}\times 100

\\ \sf\longmapsto \dfrac{8}{9}\times 100

\\ \sf\longmapsto 88.9\%

8 0
3 years ago
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