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lidiya [134]
2 years ago
13

calculate the mass of sodium trioxocarbonate(iv) produced by the complete decomposition of 16.8g of sodium hydrogen trioxocabona

te(iv)​
Chemistry
1 answer:
Usimov [2.4K]2 years ago
6 0

Answer:

question for you how does this app work old tell me

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sveticcg [70]
You would have to go to sephora and check it out 
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3 years ago
When 0.875 g. of magnesium was heated in air, 1.25 g. of magnesium oxide
Ilia_Sergeevich [38]

Answer:

1. What is the coefficient for calcium in the balanced equation?

2 Ca + 5 NaOH → 4 Na + 2 Ca(OH)2

2. The burning of 20.0 g of acetylene (C2H2) produces what mass of carbon dioxide? You must

write the equation, balance it and solve the mass-mass problem.

a. Balanced equation:

2 C2H2 + 5 O2  4 CO2 + 2 H2O

Explanation:

3 0
2 years ago
State one type of additional information that could be used to determine if these three species are closely related.
Luda [366]

Answer:

Study the bone structure of limbs.

Explanation:

Study the bone structure of limbs can be used to find out the relatedness and relationship among three species because the pattern of bones structure is similar but the structure is different from one another due to different environmental conditions. This study provides important and useful information whether the three species are closely related or not. If they have similar bone structure than we can say that there are more chances that they are closely related to each other.

5 0
2 years ago
A certain substance X has a normal freezing point of -6.4 C and a molal freezing point depression constant Kf= 3.96 degrees C.kg
Brut [27]

Answer:  1.0\times 10^2g

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=(-6.4-(13.6))^0C=7.2^0C = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte like urea)

K_f = freezing point constant = 3.96^0C/m

m= molality

\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}}\times \text{weight of solvent in kg}}

Weight of solvent (X)= 950 g = 0.95 kg  

Molar mass of non electrolyte (urea) = 60.06 g/mol

Mass of non electrolyte (urea) added = ?

7.2=1\times 3.96\times \frac{xg}{60.06 g/mol\times 0.95kg}

x=1.0\times 10^2g

Thus 1.0\times 10^2g urea was dissolved.

8 0
3 years ago
Carnegie Development stages
Darya [45]

Answer:

Stage 1: 1 days.

Stage 2: 2-3 days.

Stage 3: 4-5 days.

Stage 4: 6 days.

Stage 5 (a-c): 7-12 days.

Stage 6: c. 17 days.

Stage 7: c. 19 days.

Stage 8: c. 23 days.

7 0
2 years ago
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