Answer:
Both reactions share a common intermediate and differ only in the leaving group
Explanation:
The elimination reaction of tertiary alkyl halides usually occur by E1 mechanism. In E1 mechanism, the substrate undergoes ionization leading to the loss of a leaving group and formation of a carbocation.
Loss of a proton from the carbocation completes the reaction mechanism yielding the desired alkene.
In the cases of t-butanol and t-butyl bromide, the mechanism is the same. The both reactions proceed by E1 mechanism. The leaving groups in each case are water and chloride ion respectively.
Answer:
It is due to the nature of the reactants
Explanation:
To ignite a solid, we require more heat component compared to liquids and gases. For ignition to occur, oxygen gas combines with a reactant in most cases.
Some factors affect the rate rate at which a chemical proceeds. One of the factors is the nature of reactants.
The solid phase is very slow while the gaseous phase is rapid and fast.
solid phase < liquid phase < gas phase
Gases are free and the molecules move in all direction. They easily combine and react very fast.
In the nucleus. The nucleus is where the protons and the neutrons of the atoms are. Electrons are only have around 1/2000 of a proton's mass, so it is usually ignored
B - instering
S bddbdbdbdd
Explanation:
Here are the answers. Do note that I had to convert the enthalpy to joules and temperature to Kelvin to make the unit for entropy work out.
