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3 years ago

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calculate the mass of sodium trioxocarbonate(iv) produced by the complete decomposition of 16.8g of sodium hydrogen trioxocabona

te(iv)

1 answer:

Usimov [2.4K]3 years ago

6 0

Answer:

question for you how does this app work old tell me

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) If you prepared a solution by adding equal numbers of moles of sodium sulfite (Na2SO3) and sodium hydrogen sulfite (NaHSO3) to

sashaice [31]

The pH of the solution is mathematically given as

PH=7.21

<h3>What would be the pH of the solution?</h3>

Question Parameters:

sodium hydrogen sulfite (NaHSO3) to 50 mL of water.

Generally, the equation for the Chemical Reaction for the acid dissociation is mathematically given as

HSO3- + H2O ---> H3O+ + SO3^2-

Therefore

$pH=Pka+log\frac{A-}{Ha}$

A-=HA

pH=pKa

Since pKa NaHSO3=7.21

Hence, PH=7.21

For more information on Chemical Reaction

brainly.com/question/11231920

7 0

2 years ago

2HCl + CaCO3 → CaCl2 + H2O + CO2

zloy xaker [14]

Answer:

The amount of CaCl2 produced depends on the amount of HCl in the reaction.

Explanation:

The amount of HCl is used completelyin the reaction unlike CaCO3 which remains after reaction.

4 0

3 years ago

Is this correct im so confused.

inysia [295]

Answer:

<em>the last option!!!!</em>

Explanation:

because its right

4 0

3 years ago

When the valve between the two containers is opened and the gases allowed to mix, how does the volume occupied by the n2 gas cha

schepotkina [342]

Missing question:
Nitrogen: <span>2.0 L; </span>1.0 atm; 25°<span>C.
Oxygen: 3</span>.0 L; 2.0 atm; 25°C.
<span>When the valve between the two containers is opened, nitrogen gas moves from one container to another container and gases are mixed together, total volume of nitrogen is than:
V(nitrogen) = 2,0 L + 3,0 L = 5,0 L.</span>

4 0

3 years ago

Read 2 more answers

Purification of nickel can be achieved by electrorefining nickel from an impure nickel anode onto a pure nickel cathode in an el

Alexxandr [17]

Answer: 530 hours

Explanation:

The reduction of Nickel ions to nickel is shown as:

$Ni^{2+}+2e^-\rightarrow Ni$

$96500\times 2=193000Coloumb$ of electricity deposits 1 mole of Nickel

1 mole of Nickel weighs = 58.7 g

Given quantity = 18.0 kg = 18000 g (1kg=1000g)

58.7 g of Nickel is deposited by 193000 C of electricity

18000 g of Nickel is deposited by = $\frac{193000}{58.7}\times 18000=59182282.8C$ of electricity

$Q=I\times t$

where Q= quantity of electricity in coloumbs = 59182282.8C

I = current in amperes = 31.0 A

t= time in seconds = ?

$59182282.8C=31.0A\times t$

$t=1909105.9sec$

(1h=3600 sec)

$t=530hours$

Thus 530 hours are required to plate 18.0 kg of nickel onto the cathode if the current passed through the cell is held constant at 31.0 A

3 0

3 years ago