Mass of methane takne = 1.5g
moles of methane used = masss / molar mass = 1.5 / 16 = 0.094 moles
mass of water = 1000 g
Initial temperature of water = 25 C
final temperature = 37 C
specific heat of water = 4.184 J /g C
1) Heat absorbed by water = q =m• C• ΔT = 1000 X 4.184 x (37-25) = 50208 Joules
2) Heat absorbed by calorimeter = Heat capacity X ΔT = 695 X (37-25) = 8340 J
3) Total heat of combustion = heat absorbed by water + calorimeter = 50208 + 8340 = 58548 Joules
This heat is released by 0.094 moles of methane
So heat released by one mole of methane =
- 622851.06 Joules = 622.85 kJ / mole
4) standard enthalpy of combustion = -882 kJ / mole
Error = (882-622.85) X 100 / 882 = 24.84 %
Answer: -
Fission creates large amounts of radioactive waste.
Explanation: -
During nuclear fission, by products are formed. These by products are radioactive in nature. They give radiation. These radiation causes a lot of harm to humans including cancer and mutations.
Thus, Fission creates large amounts of radioactive waste.
Add Lime Water to the solution. If Carbon Dioxide is present the solution should go a white, milky colour due to the Calcium Hydroxide (chemical name for Lime Water) reacting with the Carbon Dioxide to form Calcium Carbonate.
Symbol Element Atomic Radius Electronegativity Ionization Energy
Ca Calcium 194 pm 1 57110 kJ/mol
Ba Barium 253 pm 0.89 3.6 x 10³ kJ/mol
As Arsenic 114 pm 2.18 12310 kJ/mol
Bi Bismuth 143 pm 2.02 8520 kJ/mol
Based on the above information.
The element with the largest radius is Ba.
The element with the highest electronegativity is As
The element with the hightest Ionization energy is Ca.
Answer:
Explanation:
Hello!
In this case, according the law of conservation of mass, we can see that, since the total mass of the Xe-F compound is 0.678 g and that of xenon is 0.526 g, we have 0.152 g as the mass of reactants equal the mass of the products. It means that we can compute the moles of each atom in the compound as shown below:
Now we divide the moles of both reactants by the moles of xenon as those are the fewest ones in order to find their subscripts in the empirical formula:
Thus, the empirical formula is:
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