6.4 * 6.02 * 10^23 = 3.8528*10^24 atoms
Don't let the fact that it's vanadium throw you off, avagadros constant stays the same for all elements
“A class C fire is an energized electrical fire. ... “Class C” is a term that distinguishes a fire from class A and class B fires. Class A is a category for fires consuming a source like fire or wood that can be extinguished with water, and class B fires are fueled by flammable liquids like gasoline.”
when hydrogen and oxygen combine then they form water as product
also in neutralization reaction water form as product
hope it helps
Explanation:
3Ca(s) + 2AlCl3(aq) -> 3CaCl2(aq) + 2Al(s)
According to the question, Ca is the limiting reactant.
Therefore, we equate Ca to Aluminium which is the product whose mass we want to find
Molar mass of Ca- 40g/mol
". ". of Al- 27g/mol
3Ca --> 2Al
3×40 --> 2×27
9.2 --> x
x = 9.2×2×27= 496.8÷120=4.14